<span>ΔE = 0
(m_alum) (c_alum) Δt - (m_water)(c_water) Δt' = 0
(30) (897) (20) - (20)(4186) Δt' = 0
Δt' = 6.42857 °C</span>
Answer:
18.1 V
Explanation:
The electric field between two parallel plates is given by the equation:

where
is the charge surface density
is the vacuum permittivity
For the plates in this problem,

So, the magnitude of the electric field is

Now we can find the potential difference between the plates, which is given by

where
d = 8.0 cm = 0.08 m is the separation between the plates
Substituting,

D 193 is the right answer if not try c because it is in between them both
Drag force is a force that resist the motion of a certain body through a fluid like air or water. This can be calculated through the equation,
D = 0.5Cρv²
where D is drag, C is the drag coefficient, ρ is the density and v is the velocity. The value therefore of b in the item above is,
b = 0.5Cρ