Please help I’m confused I need answers ASAP

A car traveling 75 km/h slows down at a constant 0.50 m/s2 just by "letting up on the gas." calculate (a) the distance the car c

Serjik [45]

Solution:

At 1st convert km/h to m/s. 1 km = 1000 m, 1 h = 3600 s, 1 km/m = 1000/3600 = 5/18 m/s

Initial velocity = 75 * 5/18 = 20.8 m/s

The car’s velocity decreases from 20.8 m/s to 0 m/s at the rate of 0.5 m/s each second. We have the final velocity, initial velocity, and the acceleration.

Now according to the equation determine the distance.

vf^2 = vi^2 + 2 * a * d

a = -0.5 m/s^2

0 = 20.8^2 + 2 * -0.5 * d

so d = 431.64 m

since we have the final velocity, initial velocity, and the acceleration. Use the following equation to determine time.

vf = vi + a * t

0 = 20.8 – 0.5 * t

Solve for t = 41 seconds

(c) the distance travels by it during the first and fifth second are.

d = vi * t + ½ * a * t^2

d1 = 20.8 * 1 – ½ * 0.5 * 1^2 = 20.55 m

The easiest way to the distance for the 5th second is:

d = vi * t + ½ * a * t^2, a = -0.5

d5 = 20.8 * 5 – ½ * 0.5 * 5^2 = 91.5 m

d6 = 20.8 * 6 – ½ * 0.5 * 6^2 = 106.8m

d6 – d5 = 15.3 m

this is the required solution.

3 0

3 years ago

Carrying Capacity is...?

Elodia [21]

Carrying capacity is the maximum amount of individuals a space can hold.

3 0

3 years ago

Please help me on questions 3 and 6, thank you! :D I'll give brainliest!

Anarel [89]

Answer:

3. if you increase your mass you also increase the gravitational pull

6. Radiant energy doesn't depend on a medium and sound energy is dependent on a medium.

Explanation:

i hope this helps-

4 0

3 years ago

Read 2 more answers

PLEASE HELP!! WILL REWARD!!

Fudgin [204]

$velocity = \frac{displacement}{time}$

Displacement measures how far it is from the starting point and the final location, which in this case is the distance between Honolulu and Los Angeles. The difference between distance and displacement is that distance measures how far the object actually travels. For example, the airplane may not fly in a straight line and it may have detours, making the distance much greater than the displacement.

On the other hand, the plane could fly at different speeds at different periods of time. It will be so much more complicated if we have to calculate it. That's why this question only asks you to calculate the average velocity of the plane, ie. $\frac{total displacement}{total time}$

So, we have

the required average velocity = $\frac{2558}{5}$

= 511.6 miles/hour

Hope this helps!

6 0

3 years ago

Read 2 more answers

Two rather unequal cars are competing in a drag race. For simplicity, let's assume that the accelerations of the cars are consta

MA_775_DIABLO [31]

Answer:

car1: a=3.1m/s^2 , car2: a=6.1m/s^2

(a) 1/2*3.1*t^2= 1/2*6.1*(t-0.9)^2

1.55t^2= 3.05(t^2-1.8t+0.81)= 3.05t^2-5.49t+2.4705

1.5t^2-5.49t+2.4705= 0

t= 3.13457 = 3.14[s] after.

(b) d= 1/2*3.1*3.13457^2= 15.23[m] approx.

(c) car1: v=at = 3.1*3.13457= 9.717m/s

car2: v=at = 6.1*(3.13457-0.9)= 13.631m/s

13.631-9.717= 3.914 = 3.91[m/s] faster than car1.

6 0

4 years ago