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3 years ago

What do a hypothesis and scientific law have in common?

Chemistry

1 answer:

Eva8 [605]3 years ago

4 0

Answer:

When reading scientific articles (and many other articles on Futurism), you’ll likely to come across the terms “hypothesis,” “theory,” ” and “law.” In the scientific community, these words have very specific definitions; however, once you get outside the scientific community, these definitions can be unclear, as the same terms are used differently in a colloquial context.

Explanation:

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An airplane travels 2100 km at 1000km/hE. It encounters a wind and slows to 800 km/h E for the next 1300 km. What is the average

Deffense [45]

Answer:

The average velocity of the airplane for this trip is 1684.21 km/h

Explanation:

Average velocity is the rate of change of displacement with time. That is,

Average velocity = $\frac{Displacement }{Change in time}$ = Δx / Δt = $\frac{x2 - x1}{t2 - t1}$

Now we will calculate the time taken by the airplane for the first motion before it encounters a wind.

From,

Velocity = $\frac{Distance traveled}{Time taken}$

Time = $\frac{Distance traveled}{Velocity}$

Therefore, Time = $\frac{2100km }{1000km/h}$

Time = 2.1h

This is the time taken before the airplane encounters a wind.

Hence, t1 = 2.1h

Now, For the time taken by the airplane when it encounters a wind

Also from,

Velocity = $\frac{Distance traveled}{Time taken}$

Time = $\frac{Distance traveled}{Velocity}$

Therefore, Time = $\frac{1300km }{800km/h}$

Time = 1.625h

Hence, t2 = 1.625h

Now, to calculate the average velocity

Average velocity = $\frac{x2 - x1}{t2 - t1}$

x1= 2100, x2= 1300, t1= 2.1h and t2= 1.625h

Hence, Average velocity = $\frac{1300 - 2100}{1.625 - 2.1}$

Average velocity = 1684.21 km/h

7 0

3 years ago

Suppose you were given a substance and asked to determine weather or not it was a plasma. Write the characteristics you would lo

Sphinxa [80]

Electrical conductivity, electromagnetism, and temperature are the features that one would look for in order to determine plasma. Plasma refers to a hot ionized gas possessing high electrical conductivity. It is electrically neutral with negative and positive particles. It can be considered the most abundant form of matter in the universe.

The features of plasma are substantially distinct from those of the usual neutral gases so that plasmas are regarded as a different fourth state of matter.

5 0

3 years ago

Read 2 more answers

Approximately how much of the world’s oil and natural gas reserves are believed to be in the arctic? View Available Hint(s) Appr

Gnoma [55]

Answer:

1/4 or 25%

Explanation:

The Arctic region of the earth refers to that part of the earth around the north pole region. Hence, when we are talking about latitude O degrees North, the areas around this geographical location is referred to as the arctic.

Now , there is an estimated 1/4 or 25% of the world’s oil and natural gas here. Unfortunately, these are yet accessible because of the amount of ice or snow covering. With increase in technological advancements, this might be accessible in the nearest future

7 0

3 years ago

Refer to the following elements to answer the questions below. 126C168O11H147N3216S3115P, where the upper index is atomic mass a

hjlf

<u>Answer:</u> The number of valence electrons in sulfur atom are 6.

<u>Explanation:</u>

The isotopic representation of sulfur atom is $_{16}^{32}\textrm{S}$

Valence electrons are defined as the electrons that are present in the outer most orbital of an atom. Electrons present in the orbitals having highest principle quantum number are termed as valence electrons.

Sulfur is the 16th element of the periodic table having 16 electrons.

Electronic configuration of sulfur atom is $1s^22s^22p^63s^23p^4$

The number of valence electrons present in sulfur atom are 2 + 4 = 6

Hence, the number of valence electrons in sulfur atom are 6.

3 0

3 years ago

An unknown gas effuses 2. 165 times faster than xe. what is the molar mass of the gas? show the set up and answer with unit

enot [183]

27.94 g/mole is the molar mass of the unknown gas.

Use Graham's Law, which indicates that the square root of a gas's molar mass determines its rate of effusion.

The following equation compares two distinct gases, (a) and (b), and expresses this:

sqrt(M(b)/M) = R(a)/R(b) (a)

R is the effusion rate.

square root = sqrt

the molar mass, M

In response to your query, if gas (a) is the unknown gas and Xe(M = 131 g/mol) is the second gas, we have:

sqrt(M(Xe)/M(a) = 2.165, where R(a)/R(Xe)

Square both sides, and you get:

(2.165)² = 131 g/mol/ M (a)

M(a)(2.165)² = 131

M(a) is equal to 131/(2.165)² = 27.94 g/mol.

Having a molar mass of 27.94 g/mol, the unknown gas.

Learn more about Graham's law of effusion here brainly.com/question/22359712

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8 0

2 years ago