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taurus [48]
3 years ago
6

What is the relationship between the degree of ionization and conductivity?

Chemistry
1 answer:
lidiya [134]3 years ago
4 0

Answer:

B

Explanation:

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Giving brainliest please help with this question
siniylev [52]

Answer:

B

Explanation:

6 0
3 years ago
1. Gases are made up of molecules which are relatively far apart.
bulgar [2K]
The answer is A) 1...
6 0
3 years ago
What data do you need to determine the specific heat capacity of a substance?
strojnjashka [21]

Speific heat capacity is measured with the aid of determining how a whole lot warmth electricity is needed to increase one gram of a substance one digree Celsius. The Speific heat capacity of water is 4.2 joules per gram per degree Celsius or 1 calorie in step with gram per digree Celsius.

The specific heat capacity is defined as the amount of heat (J) absorbed consistent with unit mass (kg) of the substance while its temperature increases 1 ok (or 1 °C), and its units are J/(kg k) or J/(kg °C).

Factors specific heat capacity relate to are temperature and strength.

The Speific heat capacity C can be measured as q = mC∆T

Or, C = q/m∆T

where,

C is the specific heat capacity

q is the quantity of heat required

m is the mass

∆T is the change in temperature

As a consequence so as to degree the specific heat capacity we need to recognize mass of the substance, quantity of heat lost or gain by the substance and the exchange in temperature.

Lear more about Speific heat capacity here: brainly.com/question/17162473

#SPJ4

6 0
1 year ago
What is the potential energy of a rock with a mass of 10 kg while sitting on a cliff that is 15 m high
KonstantinChe [14]
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7 0
3 years ago
How much water should be added to 4.3 moles of LiBr to prepare a 2.05 m solution?
arsen [322]

Answer:

2.1 kg of water

Explanation:

Step 1: Given data

  • Moles of lithium bromide (solute): 4.3 moles
  • Molality of the solution (m): 2.05 m (2.05 mol/kg)
  • Mass of water (solvent): ?

Step 2: Calculate the mass of water required

Molality is equal to the moles of solute divided by the kilograms of solvent.

m = moles of solute/kilograms of solvent

kilograms of solvent = moles of solute/m

kilograms of solvent = 4.3 mol /(2.05 mol/kg) = 2.1 kg

8 0
2 years ago
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