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Lubov Fominskaja [6]
2 years ago
11

A compound has a percent composition of 15.24% sodium (molar mass = 22.99

Chemistry
1 answer:
RUDIKE [14]2 years ago
8 0

The empirical formula of the compound obtained from the question given is NaBrO₃

<h3>Data obtained from the question </h3>
  • Sodium (Na) = 15.24%
  • Bromine (Br) = 52.95%
  • Oxygen (O) = 31.81%
  • Empirical formula =?

<h3>How to determine the empirical formula </h3>

The empirical formula of the compound can be obtained as illustrated below:

Divide by their molar mass

Na = 15.24 / 22.99 = 0.663

Br = 52.95 / 79.90 = 0.663

O = 31.81 / 16 = 1.988

Divide by the smallest

Na = 0.663 / 0.663 = 1

Br = 0.663 / 0.663 = 1

O = 1.988 / 0.663 = 3

Thus, the empirical formula of the compound is NaBrO₃

Learn more about empirical formula:

brainly.com/question/24297883

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If 12.5 grams of the original sample of cesium-137 remained after 90.6 years, what was the mass of the original sample?
myrzilka [38]

Answer:

Mass of original sample = 100 g

Explanation:

Half life of cesium-137 = 30.17 years

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{30.17}\ year^{-1}

The rate constant, k = 0.02297 year⁻¹

Time = 90.6 years

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Initial concentration [A_0] = ?

Final concentration [A_t] = 12.5 grams

Applying in the above equation, we get that:-

12.5\ g=[A_0]e^{-0.02297\times 90.6}

[A_0]=\frac{12.5}{e^{-0.02297\times 90.6}}\ g=100\ g

<u>Mass of original sample = 100 g</u>

8 0
3 years ago
The meselson-stahl experiment demonstrated that DNA replication is semi conservative in the figure semi conservative replication
Vlad1618 [11]

Answer:

The correct answer will be option-D.

Explanation:

The semi-conservative mode of replication is the common method of replication used by mostly organisms on earth which were demonstrated by the Meselson and Stahl in 1958.

They used the isotopes of the nitrogen which contains extra neuron which makes the nitrogen-heavy and cultured them in bacteria

The experiment concluded that newly replicated double stranded DNA contains one newly synthesized DNA strand which is complementary to another parental strand. Thus new DNA molecule has one parental strand while other newly synthesized strand.

This is best illustrated by the option-D in the figure and therefore is the correct answer.

7 0
4 years ago
Read 2 more answers
Explain Wurtz reaction with an example ~​
Deffense [45]

Wurtz reaction is a special type of organic reaction involving the synthesis of aliphatic hydrocarbons from two molecules of an alkyl halide and two atoms of sodium in the presence of dry ether solution

Please bear in mind that wurtz reaction fails whenever tertiary alkyl halides are used.

An example of Wurtz reaction is given below:

2R – X + 2Na → R–R + 2Na + X−

<h3>What are organic compounds?</h3>

Organic compounds can simply be defined as those classes of organic molecules which contain carbon atoms covalently bonded to hydrogen atoms (C-H bonds).

Below are some few general characteristics of organic compounds:

  • All organic compounds contain carbon.

  • Most of them are flammable.

  • They are all soluble in non-polar solvents

  • Most organic compounds / substances are covalently bonded molecules

Some classes of organic compounds are:

  • Alkanes
  • Alkenes
  • Alkenes

So therefore, Wurtz reaction is a special type of organic reaction involving the synthesis of aliphatic hydrocarbons from two molecules of an alkyl halide and two atoms of sodium in the presence of dry ether solution

Learn more about organic compounds:

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#SPJ1

5 0
2 years ago
What is the percentage yield of O2 if 12.3 g of KClO3 (molar mass 123 g) is decomposed to produce 3.2 g of O2 (molar mass 32 g)
My name is Ann [436]

Answer:

The percentage yield of O2 is 66.7%

Explanation:

Reaction for decomposition of potassium chlorate is:

2KClO₃ →  2KCl  +  3O₂

The products are potassium chloride and oxygen.

Let's find out the moles of chlorate.

Mass / Molar mass = Moles

12.3 g / 123 g/mol = 0.1 mol

So ratio is 2:3, 2 moles of chlorate produce 3 mol of oxygen.

Then, 0.1 mol of chlorate may produce (0.1  .3)/ 2 = 0.15 moles

Let's convert the moles of produced oxygen, as to find out the theoretical yield.

0.15 mol . 32 g/ 1mol = 4.8 g

To calculate the percentage yield, the formula is

(Produced Yield / Theoretical yield) . 100 =

(3.2g / 4.8g) . 100 = 66.7 %

8 0
4 years ago
In a neutralization reaction, 24.6 mL of 0.300 M H2SO4(aq) reacts completely with 20.0 mL of NaOH(aq). The products are Na2SO4(a
stiv31 [10]

Answer : The concentration of the NaOH solution is, 0.738 M

Explanation :

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=0.300M\\V_1=24.6mL\\n_2=1\\M_2=?\\V_2=20.0mL

Putting values in above equation, we get:

2\times 0.300M\times 24.6mL=1\times M_2\times 20.0mL

M_2=0.738M

Thus, the concentration of the NaOH solution is, 0.738 M

7 0
3 years ago
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