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2 years ago

Describe how a speed-time graph shows an object that is stationary

Physics

1 answer:

cupoosta [38]2 years ago

7 0

Answer:

When in the graph the line is horizontal it states that the moving object is stationary

Explanation:

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A runner runs around the track consisting of two parallel lines 96 m long connected at the ends by two semi circles with a radiu

Zielflug [23.3K]

-0 m/s
- average velocity=displacement/time
- the runners displacement is zero so her average velocity must be zero

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3 years ago

Describe an object’s motion when balanced forces act on it

Alinara [238K]

Balanced forces do not cause a change in motion. When balanced forces act on an object at rest, the object will not move. If you push against a wall, the wall pushes back with an equal

3 0

3 years ago

Read 2 more answers

Joe and Jim start at rest at the starting line of a race track. Both runners accelerate at the same rate, but Joe accelerates fo

eduard

Answer:

Vf₂ = 2 Vf₁

It shows that final speed of Joe is twice the final speed of Jim.

Explanation:

First, we analyze the final speed of Jim by using first equation of motion:

Vf₁ = Vi + at

where,

Vf₁ = final speed of Jim

Vi = initial speed of Jim = 0 m/s

a = acceleration of Jim

t = time of acceleration for Jim

Therefore,

Vf₁ = at ---------------- equation (1)

Now, we see the final speed of Joe. For Joe the parameters will become:

Vf = Vf₂

Vi = 0 m/s

a = a

t = 2t

Therefore,

Vf₂ = 2at

using equation (1):

<u>It shows that final speed of Joe is twice the final speed of Jim.</u>

3 0

3 years ago

An infinite plane of charge has a surface charge density of 5 µC/m2 . How far apart are the equipotential surfaces whose potenti

Lostsunrise [7]

Answer:

Distance in mm will be 0.3718 mm

Explanation:

We have given charge surface charge density $\rho _s=5\mu c/m^2=5\times 10^{-6}\mu c/m^2$

We know that electric field due to surface charge density is given by

$E=\frac{\rho _S}{2\epsilon _0}=\frac{5\times 10^{-6}}{2\times 8.85\times 10^{-12}}=2.824\times 10^5Volt/m$

We have given potential difference V = 105 volt

We know that potential difference is given by $V=Ed$

So $105=2.824\times 10^5\times d$

$d=37.181\times 10^{-5}m=0.3718mm$

8 0

3 years ago

The spring constant, k, for a 22cm spring is 50N/m. A force is used to stretch the spring and when it is measured again it is 32

lutik1710 [3]

Answer:

Explanation:

Given parameters:

Original length = 22cm

Spring constant, K = 50N/m

New length = 32cm

Unknown

Force applied = ?

Solution:

The force applied on a spring can be derived using the expression below;

Force = KE

k is the spring constant

E is the extension

extension = new length - original length

extension = 32cm - 22cm = 10cm

convert the extension from cm to m;

100cm = 1m;

10cm will give 0.1m

So;

Force = 50N/m x 0.1m = 5N

8 0

3 years ago