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Sergio [31]
3 years ago
10

All nets that will make a triangular prism

Mathematics
1 answer:
icang [17]3 years ago
8 0
Tap on the picture above.

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Please help mee! &lt;33<br><br> y+4=-4(x+2)<br> in standard form! &lt;3
Pachacha [2.7K]

Answer:

y = -4x - 12

Step-by-step explanation:

y + 4 = -4(x + 2)

y = -4x -8 - 4

y = -4x - 12

6 0
3 years ago
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Which statements are true about trapezoid ABCD and its translated image, A'B'C'D'? Select two options.
V125BC [204]

Answer: 1 and 4 are correct

Step-by-step explanation: good luck!

7 0
3 years ago
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In this line of circles, the ratio of red circles to blue circles is 1:3 How many more circles would need to be added to make th
zaharov [31]

Answer:

The number of red circles to be added would be equal to 8 times the original amount of red circles

Step-by-step explanation:

Let

x ----> the number of red circles

y ----> the number of blue circles

Originally

\frac{x}{y}=\frac{1}{3}

y=3x ----> equation A

How many more circles would need to be added to make the ratio of red to blue 3:1

Let

n ----> the  number of additional red circles

\frac{x+n}{y}=\frac{3}{1} ----> equation B

substitute equation A in equation B

\frac{x+n}{3x}=\frac{3}{1}

solve for n

x+n=9x\\n=9x-x\\n=8x

therefore

The number of red circles to be added would be equal to 8 times the original amount of red circles

5 0
3 years ago
Si una empresa obtiene un préstamo de S/3000 a seis años de plazo, con una tasa de interés compuesto del 15 % anual capitalizabl
Debora [2.8K]

Answer:

VF= $3.281,42

Interes= 3.281,42 - 3.000= $281.42

Step-by-step explanation:

Dada la siguiente información:

Prestamo (P)= $3.000

Tasa (i)= 0,015/2= 0,0075

Cantidad de periodos (n)= 6*2= 12 semestres

<u>Para calcular el valor final del prestamos, tenemos que usar la siguiente formula:</u>

VF= P*(1 + i)^n

VF= 3.000*1,0075^12

VF= $3.281,42

Interes= 3.281,42 - 3.000= $281.42

8 0
3 years ago
a. 0.98 – 0.053 b. 0.67 – 0.4 c. 0.3 – 0.002 d. 3.2 – .789 e. 6.53 – 4.298 f. 6 – 4.32 g. 7 – 3.574 h. 4.83 – 1.8 i. 3.7 – 1.8 j
Pavlova-9 [17]

a. 0.927

We have:

0.98 – 0.053

We can re-write it as:

0. 9 8 0 -

0. 0 5 3

Moving digits to the right:

0. 9 7 10 -

0. 0 5 3

Digit-per-digit subtraction:

0. 9 2 7


b. 0.27

We have:

0.67 – 0.4

We can re-write it as:

0. 6 7 -

0. 4 0

Digit-per-digit subtraction:

0. 2 7


c. 0.298

We have:

0.3 – 0.002

We can re-write it as:

0. 3 0 0 -

0. 0 0 2

Moving digits to the right:

0. 2 10 0 -

0. 0 0 2

Again:

0. 2 9 10 -

0. 0 0 2

Digit-per-digit subtraction:

0. 2 9 8


d. 2.411

We have:

3.2 – .789

We can re-write it as:

3. 2 0 0 -

0. 7 8 9

We need to rewrite the first term by moving digits to the right several times:

3. 2 0 0 = 2. 12 0 0 = 2. 11 10 0 = 2. 11 9 10

So now we have:

2. 11 9 10 -

0. 7 8 9

Digit-per-digit subtraction:

2. 4 1 1


e. 2.232

We have:

6.53 – 4.298

We can re-write it as:

6. 5 3 0 -

4. 2 9 8

We need to rewrite the first term by moving digits to the right several times:

6. 5 3 0 = 6. 5 2 10 = 6. 4 12 10

So now we have:

6. 4 12 10 -

4. 2 9 8

Digit-per-digit subtraction:

2. 2 3 2


f. 1.68

We have:

6 – 4.32

We can re-write it as:

6. 0 0 -

4. 3 2

We need to rewrite the first term by moving digits to the right several times:

6. 0 0 = 5. 10 0 = 5. 9 10

So now we have:

5. 9 10 -

4. 3 2

Digit-per-digit subtraction:

1. 6 8


g. 4.426

We have:

7 – 3.574

We can re-write it as:

7. 0 0 0 -

3. 5 7 4

We need to rewrite the first term by moving digits to the right several times:

7. 0 0 0 = 6. 10 0 0 = 6. 9 10 0 = 6. 9 9 10

So now we have:

6. 9 9 10 -

3. 5 7 4 =

Digit-per-digit subtraction:

3. 4 2 6


h. 3.03

We have:

4.83 – 1.8

We can re-write it as:

4. 8 3 -

1. 8 0

We can immediately do the digit-per-digit subtraction:

3. 0 3


i. 2.9

We have:

3.7 – 1.8

We can re-write it as:

3. 7 -

1. 8

We need to rewrite the first term by moving digits to the right:

3. 7 = 2. 17

So now we have:

2. 17 -

1. 8 =

Digit-per-digit subtraction:

2. 9


j. 4.538

We have:

16.17 – 11.632

We can re-write it as:

1 6 . 1 7 0 -

1 1 . 6 3 2

We need to rewrite the first term by moving digits to the right:

1 6. 1 7 0 = 1 6. 1 6 10 = 1 5. 11 6 10  

So now we have:

1 5. 11 6 10 -

1 1. 6 3 2 =

Digit-per-digit subtraction:

0 4. 5 3 8

3 0
3 years ago
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