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stiv31 [10]
3 years ago
7

Sulfur has an atomic number of 16 what is the ground-state electron configuration of sulfur​

Chemistry
2 answers:
guapka [62]3 years ago
5 0

Answer:

1s2 2s2 2p6 3s2 3p4

Explanation:

For ground state atoms you need to fill the orbitals in order.

Orbital s has max 2 electrons

Orbital p has max 6 electrons

Level 1 only has s orbital

Level 2 has s and p orbitals

Level 3 has s, p and d orbitals

You fill them in order until you reach 16 electrons:

1s2 2s2 2p6 3s2 3p4

Sphinxa [80]3 years ago
3 0

Answer: 1s^22s^22p^63s^23p^4

Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.

The electrons are filled according to Afbau's rule in order of increasing energies. Sulphur with atomic number of 16 will have 16 electrons and thus the ground state electronic configuration is:

S:16:1s^22s^22p^63s^23p^4

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Graduated cylinder is filled to 41.5mL with water, and a price of granite is placed in the cylinder displacing the level to 47.6
Y_Kistochka [10]

Answer:

6.1 cm³

Explanation:

To solve this problem we first need to keep in mind <em>Archimedes' principle</em>:

  • The volume of water (or any fluid) displaced by a submerged object is equal to the object's volume.

With that in mind we <u>calculate the volume of the granite piece in mililiters</u>:

  • Volume displaced = 47.6 mL - 41.5 mL = 6.1 mL
  • Volume of the granite piece = 6.1 mL

Given that one cubic centimeter is equal to one mililiter, the volume of the granite piece in cm³ is 6.1 cm³.

8 0
3 years ago
An unknown amount of mercury (II) oxide was decomposed in the lab. Mercury metal was formed and 5.20 L of oxygen was released at
Yakvenalex [24]

Answer:

  • <u>68.3g</u>

Explanation:

<u>1. Word equation:</u>

  • <em>mercury(II) oxide → mercury + oxygen </em>

<u>2. Balanced molecular equation:</u>

  • 2HgO → 2Hg + O₂(g)

<u>3. Mole ratio</u>

Write the ratio of the coefficients of the substances that are object of the problem:

       2molHgO/1molO_2

<u>4. Calculate the number of moles of O₂(g)</u>

Use the equation for ideal gases:

          pV=nRT\\\\\\n=\dfrac{pV}{RT}\\\\\\n=\dfrac{0.970atm\times5.20L}{0.08206atm.L/K.mol\times 390.0K}\\\\\\n=0.1576mol

<u>5. Calculate the number of moles of HgO</u>

         \dfrac{2molHgO}{1molO_2}\times 0.1576molO_2=0.315molHgO

<u>6. Convert to mass</u>

  • mass = # moles × molar mass

  • molar mass of HgO: 216.591g/mol

  • mass = 0.315mol × 216.591g/mol = 68.3g

7 0
3 years ago
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riadik2000 [5.3K]

29-23 is 6, so 6 degrees

3 0
3 years ago
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13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the
wariber [46]

Answer:

13. 2.60 L.

14. 2.40 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and T are constant, and have different values of P and V:

(P₁V₁) = (P₂V₂)

<em>13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the  pressure  is increased to 1.25 atm.</em>

P₁ = 0.755 atm, V₁ = 4.31 L.

P₂= 1.25 atm, V₂ = ??? L.

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<em>14. 600.0 mL of a gas is at a pressure of 8.00 atm. What is the volume of the gas at 2.00  at m.</em>

P₁ = 8.0 atm, V₁ = 600.0 mL.

P₂= 2.0 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (8.0 atm)(600.0 mL)/(2.0 atm) = 2400/0 mL = 2.40 L.

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marusya05 [52]

Answer:

A) Oxygen

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Explanation:

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