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stiv31 [10]
3 years ago
7

Sulfur has an atomic number of 16 what is the ground-state electron configuration of sulfur​

Chemistry
2 answers:
guapka [62]3 years ago
5 0

Answer:

1s2 2s2 2p6 3s2 3p4

Explanation:

For ground state atoms you need to fill the orbitals in order.

Orbital s has max 2 electrons

Orbital p has max 6 electrons

Level 1 only has s orbital

Level 2 has s and p orbitals

Level 3 has s, p and d orbitals

You fill them in order until you reach 16 electrons:

1s2 2s2 2p6 3s2 3p4

Sphinxa [80]3 years ago
3 0

Answer: 1s^22s^22p^63s^23p^4

Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.

The electrons are filled according to Afbau's rule in order of increasing energies. Sulphur with atomic number of 16 will have 16 electrons and thus the ground state electronic configuration is:

S:16:1s^22s^22p^63s^23p^4

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Two samples of carbon tetrachloride were decomposed into their constituent elements. One sample produced 32.4 g of carbon and 37
Gnoma [55]

Answer:

The answer to your question is:

Explanation:

Law of constant composition states that a given compound always contains its component elements in a fixed ratio.

Data

Sample 1   32.4 g of C and 373 g of Cl

Sample 2  12.3 g of C and 112 g of Cl

Convert the grams to moles and compare the ratios

Sample 1                                             Sample 2

          12 g of C --------------- 1 mol                        12 g of C --------------  1 mol

          32.4 g    ----------------  x                              12.3         -------------   x

          x = (32.4 x 1) / 12                                        x = (12.3 x 1) / 12

          x = 2.7 moles of C                                     x = 1.025 moles of C

          35.5 g of Cl ----------   1 mol                       35.5 g of Cl ----------  1 mol

          373 g  ------------------    x                             112 g of Cl   -----------  x

         x = (373 x 1) / 35.5                                       x = (112 x 1) / 35.5

         x = 10.5 moles of Cl                                    x = 3.15 moles of Cl

Ratio

        10.5 / 2.7 = 3.9                                             3.15/1.025 = 3.1

The ratio must be equal in both samples to say that the law is constant. So the answer is NO.

2.-

1) H3PO4                           3 hydrogens

2) Na2HPO4                     1 hydrogen

3) Ca(HCO3)2                   2 hydrogens

4) Ba(C2H3O2)2               6 hydrogens

                           

8 0
3 years ago
How does the octet rule allow you to predict the charge an ion will have?
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 <span>Because of the octet rule, it is easy to predict the charge of the ion of an element. Look at the number of valence electrons the element has. If it is between 1 and 4 the atom will most likely loose those electrons to become stable, making it a positive ion with the charge of the number of electrons it will lose. If it has between 4 and 8 valence electrons the atom will most likely gain electrons to achieve a full outer ring of 8 electrons. Its atom will have a negative charge of the number of electrons it needs to have 8 total. Hope I Helped If You Don't Mind May I Have A Brainliest Answer Please? :)</span>
6 0
3 years ago
5. Azulene is a beautiful blue hydrocarbon. If 0.106 g of the compound is burned in oxygen, 0.364 g of CO2 and 0.0596 g of H2O a
max2010maxim [7]

<u>Answer:</u> The empirical and molecular formula for the given organic compound is CH and C_{10}H_{10} and it is not an alkane.

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=0.364g

Mass of H_2O=0.0596g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.364 g of carbon dioxide, \frac{12}{44}\times 0.364=0.0993g of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.0596 g of water, \frac{2}{18}\times 0.0596=0.0067g of hydrogen will be contained.

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.0993g}{12g/mole}=0.00828moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.0067g}{1g/mole}=0.0067moles]

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0067 moles.

For Carbon = \frac{0.00828}{0.0067}=1.23\approx 1

For Hydrogen = \frac{0.0067}{0.0067}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 1

The empirical formula for the given compound is CH

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 128.2 g/mol

Mass of empirical formula = 13 g/mol

Putting values in above equation, we get:

n=\frac{128.2g/mol}{13g/mol}=9.86\approx 10

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(1\times 10)}H_{(1\times 10)}=C_{10}H_{10}

The general formula of an alkane is C_nH_{(2n+2)}, where n = any natural number

Here, n = 10 and it does not satisfy being an alkane

Hence, the empirical and molecular formula for the given organic compound is CH and C_{10}H_{10} and it is not an alkane.

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