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kobusy [5.1K]
4 years ago
12

How many moles of ethyl alcohol, C2H6O, are in a 18.0 g sample?

Chemistry
1 answer:
Arte-miy333 [17]4 years ago
4 0
To find moles in this sample, you would divide grams by molar mass of ethyl alcohol
(18.0g)/(46.07g/mol) = 0.391mol C2H6O
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There are 0.55 moles of carbon dioxide gas in a 15.0 L container. This container is at a temperature of 300 K. What is the press
sertanlavr [38]

Answer:

\large \boxed{\text{D.) 91 kPa}}

Explanation:

We can use the Ideal Gas Law — pV = nRT

Data:

V = 15.0 L

n = 0.55 mol

T = 300 K

Calculation:

\begin{array}{rcl}pV & =& nRT\\p \times \text{15.0 L} & = & \text{0.55 mol} \times \text{8.31 kPa$\cdot$ L$\cdot$K$^{-1}$mol$^{-1}\times$ 300 K}\\15.0p & = & \text{1370 kPa}\\p & = & \textbf{91 kPa}\end{array}\\\text{The pressure in the container is $\large \boxed{\textbf{91 kPa}}$}

6 0
3 years ago
What property can be used to tell the difference between two minerals, if they have the same hardness?
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Some properties to differentiate between the minerals include:

Ductility
Malleability
Luster
Particle Size
Ability to react with chemicals
etc....
6 0
3 years ago
The plunger on a bicycle pump with a 400 mL volume cylinder is
Kobotan [32]

Answer:

The answer to your question is V2 = 66.7 ml

Explanation:

Data

Volume 1 = V1 = 400 ml

Pressure 1 = P1 = 1 atm

Volume 2 = V2 = ?

Pressure 2 = P2 = 6 atm

Process

1.- To solve this problem use Boyle's law

                     P1V1 = P2V2

-solve for V2

                     V2 = P1V1 / P2

-Substitution

                      V2 = (1)(400) / 6

-Simplification

                      V2 = 400 / 6

-Result

                      V2 = 66.7 ml

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The heat in particles travels through convection at a certain speed depending on what density a mass has.

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