Given data:
Mass of copper (m) = 20.0 g
Initial temperature of Copper (T1)= 25 C
Final temperature = T2
Heat absorbed by copper (Q) = 475 J
Specific heat of Copper (c) = 0.385 J/g C
Formula:
Q = mcΔT
= mc(T2-T1)
475 = 20*0.385*(T2-25)
62.08 = T2-25
T2 = 87.08 = 87.1 C
Answer:
Mass = 65.4 g
Explanation:
Given data:
Mass of Al₂O₃ = 25 g
Mass of AlCl₃ = ?
Solution:
Chemical equation:
Al₂O₃ + 6HCl → 2AlCl₃ + 3H₂O
Number of moles of Al₂O₃:
Number of moles = mass/ molar mass
Number of moles = 25 g/ 101.96 g/mol
Number of moles = 0.2452 mol
Now we will compare the moles of Al₂O₃ and AlCl₃.
Al₂O₃ : AlCl₃
1 : 2
0.2452 : 2×0.2452 = 0.4904 mol
Mass of AlCl₃:
Mass = number of moles × molar mass
Mass = 0.4904 mol × 133.34 g/mol
Mass = 65.4 g
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Answer:
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Explanation:
<em>the terms strong and weak as applied to acids. As a part of this it defines and explains what is meant by pH, Ka and pKa.
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<em>It is important that you don't confuse the words strong and weak with the terms concentrated and dilute.
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<em>As you will see below, the strength of an acid is related to the proportion of it which has reacted with water to produce ions. The concentration tells you about how much of the original acid is dissolved in the solution.
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<em>It is perfectly possible to have a concentrated solution of a weak acid, or a dilute solution of a strong acid. </em>