Answer:
50 kg
Step-by-step explanation:
Given that:
SMALL HELICOPTERS:
Weight of small helicopters = 3kg
Weight of shipping container = 20kg
LARGE HELICOPTERS:
Weight of large helicopters = 4kg
Weight of shipping container = 10kg
Number of helicopters each shipping container can hold = s ; all of the packed containers will have the same shipping weight
Shipping weight :
(Weight per helicopter * number of helicopter) + weight of shipping container
Shipping weight of Small helicopters :
(3kg * s) + 20
Shipping weight Large helicopters :
(4kg * S) + 10
Shipping weight of Small helicopters = shipping weight of large helicopters
3s + 20 = 4s + 10
20 - 10 = 4s - 3s
10 = s
Hence, member of shipped helicopters = 10
Total shipping weight :
(4 * S) + 10
(4*10) + 10
40 + 10 = 50kg
Step-by-step explanation:
Turn the ratio into a fraction
2in /25 mi
You want to have miles so you can flip the fraction and mutiply to cancel out the inches
(25mi / 2in) x 5in = (25 mi x 5in) / 2in
![\bf \begin{cases} f(x)=\sqrt[3]{7x-2}\\\\ g(x)=\cfrac{x^3+2}{7} \end{cases}\\\\ -----------------------------\\\\ now \\\\ f[\ g(x)\ ]\implies f\left[ \frac{x^3+2}{7} \right]\implies \sqrt[3]{7\left[ \frac{x^3+2}{7} \right]-2}\implies \sqrt[3]{x^3+2-2} \\\\\\ \sqrt[3]{x^3}\implies x\\\\ -----------------------------\\\\ or \\\\ g[\ f(x)\ ]\implies g\left[\sqrt[3]{7x-2}\right]\implies \cfrac{\left[\sqrt[3]{7x-2}\right]^3+2}{7} \\\\\\ \cfrac{7x-2+2}{7}\implies \cfrac{7x}{7}\implies x](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%0Af%28x%29%3D%5Csqrt%5B3%5D%7B7x-2%7D%5C%5C%5C%5C%0Ag%28x%29%3D%5Ccfrac%7Bx%5E3%2B2%7D%7B7%7D%0A%5Cend%7Bcases%7D%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0Anow%0A%5C%5C%5C%5C%0Af%5B%5C%20g%28x%29%5C%20%5D%5Cimplies%20f%5Cleft%5B%20%5Cfrac%7Bx%5E3%2B2%7D%7B7%7D%20%5Cright%5D%5Cimplies%20%5Csqrt%5B3%5D%7B7%5Cleft%5B%20%5Cfrac%7Bx%5E3%2B2%7D%7B7%7D%20%5Cright%5D-2%7D%5Cimplies%20%5Csqrt%5B3%5D%7Bx%5E3%2B2-2%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Csqrt%5B3%5D%7Bx%5E3%7D%5Cimplies%20x%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0Aor%0A%5C%5C%5C%5C%0Ag%5B%5C%20f%28x%29%5C%20%5D%5Cimplies%20g%5Cleft%5B%5Csqrt%5B3%5D%7B7x-2%7D%5Cright%5D%5Cimplies%20%5Ccfrac%7B%5Cleft%5B%5Csqrt%5B3%5D%7B7x-2%7D%5Cright%5D%5E3%2B2%7D%7B7%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B7x-2%2B2%7D%7B7%7D%5Cimplies%20%5Ccfrac%7B7x%7D%7B7%7D%5Cimplies%20x)
thus f[ g(x) ] = x indeed, or g[ f(x) ] =x, thus they're indeed inverse of each other
Answer:
h=128
Step-by-step explanation:
Answer:
F(x) and g(x) are not inverse functions.
Step-by-step explanation:
In order to calculate the inverse function of a function, we have to isolate X and after that, we change the variables.
As our function f(x) is a exponentian function, we can apply logarithm with base 10 (log) in both sides in order to isolate X. Remember that log10=1.
![[tex]y=10^{(x+\frac{2}{3}) }\\\\log y=log 10^{(x+\frac{2}{3}) }\\log y = (x+\frac{2}{3}) . log10\\\frac{log Y}{log10} = (x+\frac{2}{3})\\\frac{log Y}{1} = (x+\frac{2}{3})\\log Y-\frac{2}{3}=x](https://tex.z-dn.net/?f=%5Btex%5Dy%3D10%5E%7B%28x%2B%5Cfrac%7B2%7D%7B3%7D%29%20%7D%5C%5C%5C%5Clog%20y%3Dlog%2010%5E%7B%28x%2B%5Cfrac%7B2%7D%7B3%7D%29%20%7D%5C%5Clog%20y%20%3D%20%28x%2B%5Cfrac%7B2%7D%7B3%7D%29%20.%20log10%5C%5C%5Cfrac%7Blog%20Y%7D%7Blog10%7D%20%3D%20%28x%2B%5Cfrac%7B2%7D%7B3%7D%29%5C%5C%5Cfrac%7Blog%20Y%7D%7B1%7D%20%3D%20%28x%2B%5Cfrac%7B2%7D%7B3%7D%29%5C%5Clog%20Y-%5Cfrac%7B2%7D%7B3%7D%3Dx)
[/tex]
Now we change the variables.
F(x) and g(x) are not inverse functions.
