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r-ruslan [8.4K]
2 years ago
15

Which list is organized from SMALLEST to LARGEST?

Chemistry
2 answers:
pochemuha2 years ago
6 0
 D. Planet, solar system, Galaxy universe

PilotLPTM [1.2K]2 years ago
3 0
<span>D). Planet, Solar System, Galaxy, Universe</span>
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A mixture consists of sand and an aqueous salt
Alenkinab [10]

Answer is (4).<span>
<em>
</em>
</span>

<span><em>Explanation:</em>
</span><span>
<span>The given mixture contains an </span>insoluble solid<span> <span>and an </span></span>aqueous solution of salt.  <span>The insoluble solid is </span>sand. <span>

First </span><span>we have to separate </span>insoluble solid. <span>Sand can be separated by doing </span>filtration. When we filter the mixture sand can be seen as the residue on the filter paper. 

<span>After filtering the mixture, we should collect the </span>filtrate. <span>Filtrate is the </span>salt solution. <span>By doing </span>evaporation <span>we can get the </span>solid salt. <span>

First </span>and second choices are wrong <span>because </span>after evaporating water filtration cannot be done and salt and sand will be mixed together.<span>

Salt cannot be filtered out because the salt is soluble and it is <span>in aqueous medium. Hence, third choice is wrong</span></span></span>

7 0
3 years ago
Read 2 more answers
Perform the following
Sati [7]

Answer:

35.05152

Explanation:

3 0
2 years ago
3.00 moles of nitrogen and 4.00 moles of oxygen are placed in a 35.0 L container at a temperature of 298 K. What is the pressure
Leto [7]

Answer:

i think the answer is c hoped this helped

Explanation:

7 0
2 years ago
For the gas phase decomposition of 1-bromopropane, CH3CH2CH2BrCH3CH=CH2 + HBr the rate constant at 622 K is 6.43×10-4 /s and the
ladessa [460]

<span>Answer is: activation energy of this reaction is 212,01975 kJ/mol.
Arrhenius equation: ln(k</span>₁/k₂) = Ea/R (1/T₂ - 1/T₁<span>).
k</span>₁<span> = 0,000643 1/s.
k</span>₂ = 0,00828 1/s.

T₁ = 622 K.

T₂ = 666 K.

R = 8,3145 J/Kmol.

1/T₁<span> = 1/622 K = 0,0016 1/K.
1/T</span>₂<span> = 1/666 K = 0,0015 1/K.
ln(0,000643/0,00828) = Ea/8,3145 J/Kmol · (-0,0001 1/K).
-2,55 = Ea/8,3145 J/Kmol · (-0,0001 1/K).
Ea = 212019,75 J/mol = 212,01975 kJ/mol.</span>

4 0
3 years ago
If the pH of a solution is 5.4 then the concentration of H+ ions is ___|_x10^-6
Svetllana [295]
H is 4*10^6 M , OH is 2.5*10^-9 M
6 0
3 years ago
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