The correct answer for this statement would be FALSE. It is considered false since exothermic reactions release energy, therefore, this energy can be considered more of a product, instead of the reactant. Hope this is the answer that you are looking for.
Answer:
See the explanation below, please.
Explanation:
In redox reactions (oxide reduction) the transfer of electrons between compounds occurs.
In oxidation, electrons are lost (positive charge increases). Example:
Mg ---> Mg2 + + 2 e- (passes from Mg ° to Mg 2+)
On the other hand in the reduction, electrons are gained (negative charge increases or the positive one increases). Example:
Cl2 + 2e- ---> 2 Cl- + 2 e- (passes from Cl ° to Cl-)
<u>Answer:</u> The amount of calcium hydroxide needed to react is 2.04 moles
<u>Explanation:</u>
We are given:
Moles of phosphoric acid = 1.36 moles
For the given chemical equation:
By Stoichiometry of the reaction:
2 moles of phosphoric acid reacts with 3 moles of calcium hydroxide
So, 1.36 moles of phosphoric acid will react with = 
of calcium hydroxide
Hence, the amount of calcium hydroxide needed to react is 2.04 moles
Answer: 8.45 L
Explanation:
Given that,
Initial volume (V1) = 3.5L
Initial pressure (P1) = 2.5 atm
[Since final pressure is given in torr, convert 2.5 atm to torr
If 1 atm = 760 torr
2.5 atm = 2.5 x 760 = 1900 torr
Final volume (V2) = ?
Final pressure (P2) = 787 torr
Since pressure and volume are given while temperature remains the same, apply the formula for Boyle's law
P1V1 = P2V2
3.5L x 1900 torr = 787 torr x V2
6650L•torr = 787 torr•V2
Divide both sides by 787 torr
6650L•torr/787 torr = 787 torr•V2/787 torr
8.45 L = V2
Thus, the volume of the gas at 787 torr and at the same temperature is 8.45 Liters
<span> Mg(OH)2(s) + 2HCl(aq) yield MgCl2(aq) + 2H2O(l)
grams HCl required = (50.6 grams Mg(OH)2) * (1 mol Mg(OH)2 / 58.3197 grams Mg(OH)2) * (2 mol HCl / 1 mol Mg(OH)2) * (36.453 grams HCl / 1 mol HCl) = 63.26 grams HCl required
Since there are only 45.0 grams HCl, then HCl is the limiting reactant.
theoretical yield MgCl2 = (45.0 grams HCl) * (1 mol HCl / 36.453 grams HCl) * (1 mol MgCl2 / 2 mol HCl) * (95.211 grams MgCl2 / 1 mol MgCl2) = 58.6 grams MgCl2 </span>
