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Zinaida [17]
3 years ago
12

What processes add methane (CH4) to the atmosphere​

Chemistry
1 answer:
tekilochka [14]3 years ago
8 0

Answer:

Cultivated rice paddies

Drilling of natural deposits

Fossil fuel use

Burning of biomass

Landfills

Explanation:

The bulk of the methane released into the atmosphere are as a result of various human activities.

  • Cultivated rice paddies are a known source of methane
  • The drilling of natural deposits and their exploration can release some methane into the atmosphere
  • Burning of fossil fuel and biomass is a source of methane
  • Landfills produces methane as organic materials begins to decay.
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At what pH are the moles of acid and base equal?
mihalych1998 [28]

Answer:

7

Explanation:

(Note: for a strong acid and strong base titration the equivalence point is at a pH=7. This is because at this point you have equal moles of added base as acid in the original solution. Therefore at the equivalence point the solution has formed a neutral salt and the pH is 7).

5 0
2 years ago
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Kingdom animalia includes a major phylum known as chordata, which includes the sub-phylum vertebrata. This includes lions like t
Paul [167]

Felidae is B) Family

3 0
2 years ago
Determine the number of moles of H in each sample
MissTica

C. The number of moles of H in 0.109 mole of N₂H₄ is 0.436 mole

D. The number of moles of H in 34 moles of C₁₀H₂₂ is 748 moles

<h3>C. How to determine the number of mole of H in 0.109 mole of N₂H₄</h3>

1 mole of N₂H₄ contains 4 moles of H

Therefore,

0.109 mole of N₂H₄ will contain = 0.109 × 4 = 0.436 mole of H

<h3>D. How to determine the number of mole of H in 34 mole of C₁₀H₂₂</h3>

1 mole of C₁₀H₂₂ contains 22 moles of H

Therefore,

34 mole of C₁₀H₂₂ will contain = 34 × 22 = 748 mole of H

Learn more about mole:

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5 0
1 year ago
List the three requirements for a correctly written chemical equation.2. Give one example of a word equation, one example of a f
erma4kov [3.2K]

Answer:

Requirements for a correctly written chemical equation are reactants and products, their formula and valency

Explanation:

Formula of the given compound are -

1 - Potassium Hydroxide - KOH

2 - Calcium Nitrate - Ca(NO_3)_2

The requirements for a correctly written chemical equation are -

  • Identifying reactants and products
  • Formula of reactants and products
  • Valency of elements

Example of word equation, formula equation, and chemical equation is as follows -

Aluminium + iron9(III)oxide ⇒ aluminium oxide + iron (word equation)

Al_(_s_)  + Fe_2O_3_(_s_)    ⇒   Al_2O_3_(_s_)  + Fe_(s) (formula equation)              

2Al_(_s_) + Fe_2O_3_(_s_)    ⇒   Al_2O_3_(_s_)   + 2Fe_(_s_) (chemical equation)

8 0
3 years ago
(~40 Points, Please answer and explain)
Helen [10]

Answers:

1. CO₂ < Ar    < N₂ < He;

2.  Cl₂ < CO₂ < Ar < N₂ < H₂

Step-by-step explanation:

Graham’s Law applies to the diffusion of gases:

The rate of diffusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

r = \frac{1 }{\sqrt{M}}

If you have two gases, the ratio of their rates of diffusion is

\frac{r_{2}}{r_{1}} = \sqrt{\frac{M_{1}}{M_{2}}}

1. Order of diffusion rates

According to Graham's Law, the lightest gases will have the highest diffusion rates and the heavier gases the slowest.

The molecular masses of the gases are:

Ar 39.95; CO₂ 44.01; He 4.00; N₂ 28.02

Putting them in order,we get

44.01 > 39.95 > 28.02  > 4.00

CO₂   >    Ar     >     N₂    >   He

Thus, the relative rates of diffusion are

CO₂ < Ar < N₂ < He

2. Order of molecular speeds

A postulate of the Kinetic Molecular Theory is that at a given temperature, the average kinetic energy of the molecules is directly proportional to the Kelvin temperature.

KE = ½ mv² ∝ T

           mv² ∝ T      Divide each side by m

              v² ∝ T/m

If T is constant.

              v² ∝ 1/m     Take the square root of each side

               v ∝ 1/√m

This is an inverse relationship, so the molecules with the smallest molecular mass should have the highest average speeds.

The molecular masses of the gases are:

N₂ 28.02; H₂ 2.016; Cl₂ 70.91; CO₂ 44.01; Ar 39.95

Putting them in order. we get

70.91 > 44.01 > 39.95 > 28.02  > 2.016

   Cl₂   >  CO₂  >   Ar    >     N₂   >   H₂

Thus, the relative molecular speeds are

Cl₂ < CO₂ < Ar < N₂ < H₂

4 0
3 years ago
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