Question

In order to dilute 40.0 mL of 0.600 M HCl to 0.200 M, the volume of water that would need to be added would be 200 mL. 80.0 mL. O 160 mL. 120 mL. 100 mL.​

Answer 1

Answer:

80 ml

Explanation:

Moles to start =  .04 L * .6 M/L = .024 moles

   this is how much must be in the final dilution

         .2 moles / liter * x liter  = .024 moles

                x = .024 / .2 = .12   liter final volume

           start with   . 040    then add .080   to get .12 liter

  .080 liter = 80 ml