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3 years ago

14

When dust and ash particles from a volcanic eruption block out sunlight and reduce solar radiation, Earth experiences the ______

_____ . This results in temporary climate cooling.

1 answer:

Vinil7 [7]3 years ago

6 0

The correct answer is haze effect

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Scientific notation: Convert 7.1 x 10-3 to decimal notation.

marysya [2.9K]

Answer: hey

your answer is gonna be

71000.

Explanation:

5 0

3 years ago

What acceleration will you give to a 24.5 kg

Ludmilka [50]

Heya!!

For calculate aceleration, lets applicate second law of Newton:

$\boxed{F=ma}$

<u>Δ Being Δ</u>

F = Force = 78,3 N

m = Mass = 24,5 kg

a = Aceleration = ?

⇒ Let's replace according the formula and clear "a":

$\boxed{a=78,3\ N / 24,5\ kg}$

⇒ Resolving

$\boxed{a=3.19\ m/s^{2}}$

Result:

The aceleration is <u>3,19 meters per second squared (m/s²)</u>

Good Luck!!

4 0

3 years ago

A helium-filled balloon occupies a volume of 15 cubic meters at sea level. the balloon is released and raises to a point in the

Elena L [17]

According to Boyle’s law, For a fixed amount of an ideal gas kept at a fixed temperature, P (pressure) and V (volume) are inversely proportional.

Therefore,

$P_{1} V_{1} =P_{2} V_{2}$

Given $P_{1} = 1 atm$ , $V_{1} = 15 \ cubic \ meter$ and $P_{2} = 0.75\ atm$ .

Thus,

$V_{2} = \frac{P_{1}\times V_{1} }{ P_{2} } = \frac{1\times 15}{0.75} =20 m^3$

5 0

3 years ago

A student measured the specific heat of water to be 4.29 J/g.Co. The

leonid [27]

Answer:

2.63 %.

Explanation:

Given that,

The calculated value of the specific heat of water is 4.29 J/g.C

Original value of specific heat of water is 4.18 J/g.C.

We need to find the student's percent error. The percentage error in any quantity is given by :

$P=\dfrac{|\text{original value-calculated value}|}{\text{original value}}\times 100\\\\P=\dfrac{4.29-4.18}{4.18}\times 100\\\\P=2.63\%$

So, the student's percent error is 2.63 %.

7 0

3 years ago

A cup of coffee is sitting on a table in a train that is moving with a constant velocity. The coefficient of static friction bet

Vikki [24]

Answer:

a = 2.94 m/s²

Explanation:

In order for the cup not to slip, the unbalanced force on cup must be equal to the frictional force:

Unbalanced Force = Frictional Force

ma = μR = μW

ma = μmg

a = μg

where,

a = maximum acceleration for the cup not to slip = ?

μ = coefficient of static friction = 0.3

g = acceleration due to gravity = 9.8 m/s²

Therefore,

a = (0.3)(9.8 m/s²)

<u>a = 2.94 m/s²</u>

3 0

3 years ago