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slava [35]
3 years ago
5

Mr. Cutler makes day bricks and clay tiles to sell at maker fairs. It takes him 10 minutes to make a brick and

Mathematics
1 answer:
Naily [24]3 years ago
6 0

Answer:

d

Step-by-step explanation:

You might be interested in
Solve 4x - c=k for x
kumpel [21]

Answer:

x=k/4+c/4

Step-by-step explanation:

4x-c=k

4x=k+c

x=k/4+c/4

8 0
3 years ago
Read 2 more answers
Suppose that in a normal half hour of practice, a tennis player expends 280 calories of energy.
sertanlavr [38]

Answer:

308 Calories

Step-by-step explanation:

So we start off with 280 as usual, but I will focus on the percent. The given percent is 110% "effort". What we would need to do here is, Firstly, change the percent into a decimal, and this is done by moving the decimal spot of 110%. What I mean is that 110.% and you move that little period over 2 times to the left and also remove the percent as for now because we will not need it. After that you would get 1.10. This is what we will multiply by. So if we did 280x1.10 it equals 308, and that is how I got 308

Hope this helps!

4 0
3 years ago
Henry counted 350 lockers in his school. Hayley counted 403 lockers in her school. How does the 3 in 350 compare to the 3 in 403
viva [34]
The 3 in 350 is in the hundred place and in 403 the 3 is in the ones place
3 0
3 years ago
Read 2 more answers
I really need help on this !!
Naddik [55]

Answer:

r = -1

Step-by-step explanation:

(y2-y1)/(x2-x1)=m

(r,7)=(x1,y1) and (3,4)=(x2-y2) and m=-3/5

so plug in...

(4-7)/(4-r)=-3/5

then solve for r which will get that r = -1

numerator: 4-7=-3

denominator: 4-r=5 -> 4-5=0+r -> -1=r

4 0
3 years ago
Suppose customers in a hardware store are willing to buy​ N(p) boxes of nails at p dollars per​ box, as given by the following f
AleksAgata [21]

Answer:

a) -15 unites per dollar

b) -12 units per dollar

c) -18 units per dollar

Step-by-step explanation:

We are given the following in the question:

N(p) = 100-3p^2, 1\leq p \leq 4

where N(p) is the number of boxes of nails at p dollars per​ box.

a) average rate of change of demand for a change in price from ​$2 to ​$3.

Average rate of change =

\displaystyle\frac{N(3) -N(2)}{3-2}\\\\=\frac{100-3(3)^2-(100 - 3(2)^2)}{1}\\\\= -15\text{ units per dollar}

b) instantaneous rate of change of demand when the price is ​$2

Instantaneous rate =

N'(p) = \displaystyle\frac{d(N(p))}{dp} = -6p

N'(2) = -6(2) = -12

The instantaneous rate of change of demand when the price is ​$2 is decreasing at 12 units per dollar.

c) instantaneous rate of change of demand when the price is ​$3

Instantaneous rate =

N'(3) = -6(8) = -18

The instantaneous rate of change of demand when the price is ​$3 is decreasing at 18 units per dollar.

4 0
3 years ago
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