2 angle A and B are Complementary means that the sum of their measures is 90°.
2 angle A and B are Supplementary means that the sum of their measures is 180°.
Thus, if the measure of angle A is x:
the measure of the supplement is 180°-x
the measure of the complement is 90°-x
"The measure of a supplement of an angle is 40 more than two times the measure of the complement of the angle. "
let the measure of the angle be x, then we have:
180°-x=40°+2(90°-x)
180°-x=40°+180°-2x
2x-x=40°
x=40°
Answer: 40°
6x^2 + 37x - 60 = 6x^2 - 8x + 45x - 60 = 2x(3x - 4) + 15(3x - 4) = (3x - 4)(2x + 15)
Answer:
See below
Step-by-step explanation:
![9.( {m}^{3} {n}^{5} )^{ \frac{1}{4} } \\ = m^{\frac{3}{4}}n^{\frac{5}{4}}\\ \\ 10. \sqrt[5]{ \sqrt[4]{x} } \\ = \sqrt[5]{ {x}^{ \frac{1}{4} } } \\ = {( {x}^{ \frac{1}{4} } )}^{ \frac{1}{5} } \\ = {x}^{ \frac{1}{4} \times \frac{1}{5} } \\ = {x}^{ \frac{1}{20} } \\ \\ \sqrt[5]{ \sqrt[3]{ {a}^{2} } } \\ = \sqrt[5]{ {a}^{ \frac{2}{3} } } \\ = {( {a}^{ \frac{2}{3} } )}^{ \frac{1}{5} } \\ = {a}^{ \frac{2}{3} \times \frac{1}{5} } \\ = {a}^{ \frac{2}{15} }](https://tex.z-dn.net/?f=9.%28%20%7Bm%7D%5E%7B3%7D%20%20%7Bn%7D%5E%7B5%7D%20%29%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%20%20%5C%5C%20%20%20%3D%20%20m%5E%7B%5Cfrac%7B3%7D%7B4%7D%7Dn%5E%7B%5Cfrac%7B5%7D%7B4%7D%7D%5C%5C%20%20%5C%5C%2010.%20%5Csqrt%5B5%5D%7B%20%5Csqrt%5B4%5D%7Bx%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%5B5%5D%7B%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%7B%28%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%29%7D%5E%7B%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%5C%5C%20%20%20%3D%20%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7B20%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%5Csqrt%5B5%5D%7B%20%5Csqrt%5B3%5D%7B%20%7Ba%7D%5E%7B2%7D%20%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%5B5%5D%7B%20%7Ba%7D%5E%7B%20%5Cfrac%7B2%7D%7B3%7D%20%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%7B%28%20%7Ba%7D%5E%7B%20%5Cfrac%7B2%7D%7B3%7D%20%7D%20%29%7D%5E%7B%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%5C%5C%20%20%20%3D%20%20%7Ba%7D%5E%7B%20%5Cfrac%7B2%7D%7B3%7D%20%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%7Ba%7D%5E%7B%20%5Cfrac%7B2%7D%7B15%7D%20%7D%20%20)
First, we should figure out the area of the entire face of the clock because we need that information to solve the problem. The formula for the area of a circle is A=pi*r^2. Since we know that r (radius) is equal to 11.25 feet, we can plug this in for r and solve for A: A=pi*11.25^2 which equals A=397.61 ft^2 rounded to the nearest hundredth.
Now, to find the area the hand sweeps over in 5 minutes, we should determine how much of the clock the hand sweeps over in 5 minutes. Think about it like this: since 5 minutes goes into 60 minutes 12 times (60/5=12), then 5 minutes is one twelfth of the clock's face. Therefore, we are going to divide the total area by 12 (397.61/12) to get 33.13 ft^2, so the answer is C.
I hope this helps.
I would say age of a plant to its height is a function while the others are not.
