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mojhsa [17]
3 years ago
10

How long would it take me to travel 48 milllion miles at 200000 mph?

Physics
1 answer:
MakcuM [25]3 years ago
5 0
For this question, you must divide 48 million by two hundred thousand to get your answer. The quotient of these number is 240, which if reduced to days, is exactly ten days.
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krok68 [10]

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3 years ago
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Anyone know the answer to this, would kindly appreciate it
Ipatiy [6.2K]

Answer:

The found value of r is:

r = 94.7

Explanation:

We know that

cosθ = Base / Hypotenuse

θ is the always the angle between base and hypotenuse

In this right angles triangle, the angle θ is given 63°.

Which means that the Base is 43 and the hypotenuse is r

Base = 43

Hypotenuse = r

Substitute θ=63°, Base = 43 and hypotenuse = r in the formula of cosθ mentioned above:

cos 63° = 43/r

Rearrange

r = 43/cos63°

r = 43/0.454

r= 94.7

6 0
3 years ago
Raul wants to study how pot size affects the growth of plants. To do this, he intends to purchase three different pots of varyin
hram777 [196]

Answer: The answer position may vary. But the correct answer is D. No; Raul changes more than one variable so the results will be invalid.

Explanation:

Raul's experimental set-up will not produce valid results because he intends to change more than one variable.

One variable that Raul will change is the pot size. According to the description, however, Raul will also change one other variable—the type of flower that is planted. Even though Raul plans on using flowers only, he should use the same type of flower in each pot, not different types.

Valid results are only produced when only one variable is changed at a time.

5 0
4 years ago
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3 Below, someone is trying to balance a plank with
belka [17]

Answer:

a. The moment of the 4 N force is 16 N·m clockwise

b. The moment of the 6 N force is 12 N·m anticlockwise

Explanation:

In the figure, we have;

The distance from the point 'O', to the 6 N force = 2 m

The position of the 6 N force relative to the point 'O' = To the left of 'O'

The distance from the point 'O', to the 4 N force = 4 m

The position of the 4 N force relative to the point 'O' = To the right of 'O'

a. The moment of a force about a point, M = The force, F × The perpendicular distance of the force from the point

a. The moment of the 4 N force = 4 N × 4 m = 16 N·m clockwise

b. The moment of the 6 N force = 6 N × 2 m = 12 N·m anticlockwise.

8 0
3 years ago
A 0.300 kg block is pressed against a spring with a spring constant of 8050 N/m until the spring is compressed by 6.00 cm. When
natita [175]

Answer:

a) \mu_{k} = 0.704, b) R = 0.312\,m

Explanation:

a) The minimum coeffcient of friction is computed by the following expression derived from the Principle of Energy Conservation:

\frac{1}{2}\cdot k \cdot x^{2} = \mu_{k}\cdot m\cdot g \cdot \Delta s

\mu_{k} = \frac{k\cdot x^{2}}{2\cdot m\cdot g \cdot \Delta s}

\mu_{k} = \frac{\left(8050\,\frac{N}{m} \right)\cdot (0.06\,m)^{2}}{2\cdot (0.3\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (7\,m)}

\mu_{k} = 0.704

b) The speed of the block is determined by using the Principle of Energy Conservation:

\frac{1}{2}\cdot k \cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}

v = x\cdot \sqrt{\frac{k}{m} }

v = (0.06\,m)\cdot \sqrt{\frac{8050\,\frac{N}{m} }{0.3\,kg} }

v \approx 9.829\,\frac{m}{s}

The radius of the circular loop is:

\Sigma F_{r} = -90\,N -(0.3\,kg)\cdot (9.807\,\frac{m}{s^{2}} ) = -(0.3\,kg)\cdot \frac{v^{2}}{R}

\frac{\left(9.829\,\frac{m}{s}\right)^{2}}{R} = 309.807\,\frac{m}{s^{2}}

R = 0.312\,m

5 0
4 years ago
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