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Answer:
10628.87 J
Explanation:
We are given that
Force applied =F=5592 N
Displacement=D=3.79 m
We have to find the work done in sliding the piano up the plank at a slow constant rate.
Work done=
The perpendicular component of force=
Work done =
Hence, the work done in sliding the piano up the plank at a slow constant rate=10628.87 J
Answer:
x = 50 N
Explanation:
Given that we have a net force, a mass, and acceleration, we can use the fundamental formula for force found in newton's second law which is F = m × a.
Given a mass of 150 kg, and an acceleration 3.0m/s². We can substitute these two values in our formula to calculate the magnitude of these forces or it's net force to identify the unknown force acting on our known force for this situation to work.
_______
F (Net force) = F2 (Second force which we are given) - F1 (First force) = m × a
m (mass which we are given) = 150 kg
a (acceleration which we are given) = 3.0m/s
________
So F = m × a → F2 - F1 = m × a →
500 - F1 = 150 × 3.0 → 500 - F1 = 450 →
-F1 = -50 → F1 = 50
Answer:
As per law of conservation of momentum
1 × 10 = 50× v
v = 1/5 m/S
Or
20 cm/s