Answer:
1. 4
2. 16
3. 4/3
4. 64/3
Step-by-step explanation:
Answer:
True, see proof below.
Step-by-step explanation:
Remember two theorems about continuity:
- If f is differentiable at the point p, then f is continuous at p. This also applies to intervals instead of points.
- (Bolzano) If f is continuous in an interval [a,b] and there exists x,y∈[a,b] such that f(x)<0<f(y), then there exists some c∈[a,b] such that f(c)=0.
If f is differentiable in [0,4], then f is continuous in [0,4] (by 1). Now, f(0)=-1<0 and f(4)=3>0. Thus, we have the inequality f(0)<0<f(4). By Bolzano's theorem, there exists some c∈[0,4] such that f(c)=0.
Answer:
I need more context, can you take a screenshot of the actual question or something.
Step-by-step explanation:
If we add the equations it looks like
-5y + 8x + 5y + 2x = -18+58
so 10x=40
so x=40/10=4
now let's replace x by 4 in the second equation
5y +2*4=58
5y=58-2*4=58-8=50
so y=50/5=10
so (x, y) = (2, 10)
y = 5 x +3 is the final equation when y = 5 x 3 units up
<u>Step-by-step explanation:</u>
In mathematics, a function is a relation between sets that associates to every element of a first set exactly one element of the second set. Typical examples are functions from integers to integers or from the real numbers to real numbers.
Here we have , y=5x . Function y = 5x is a straight line passing through origin and having a slope of 5 . Now we need to increment this function 3 units up i.e. y = 5x + 3 , This a straight line passing through x-axis at 
and y-axis at 3. For your reference , following graph of y= 5x and y = 5x + 3 is attached .
