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Amanda [17]
4 years ago
5

What condition must exist if a bond’s coupon rate is to equal both the bond’s current yield and its yield to maturity? Assume th

e market rate of interest for this bond is positive.
Physics
1 answer:
insens350 [35]4 years ago
6 0

The condition that must exist if a bond’s coupon rate is to equal both the bond’s current yield and its yield to maturity is that THE BOND MUST BE PRICED AT PAR.

Explanation:

  • The par value is also the amount upon which the entity calculates the interest that it owes to investors. Thus, if the stated interest rate on a bond is 10% and the bond par value is $1,000, then the issuing entity must pay $100 every year until it redeems the bond.
  • Par value is the face value of a bond. Par value is important for a bond or fixed-income instrument because it determines its maturity value as well as the dollar value of coupon payments.
  • When a bond is issued at par value it is sold for the face value amount. This generally means that the bond's market and contract rates are equal to each other, meaning that there is no bond premium or discount.

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A ball is thrown vertically upward. As it rises, what happens to its total energy?.
diamong [38]

The total energy of a ball stays constant as it is thrown upward because potential energy increases while kinetic energy decreases. When the ball reaches its maximum height, the velocity is zero. Therefore, only potential energy exists rather than kinetic energy.

The thrower's movement imparts kinetic energy to a ball thrown vertically. The maximum height that can be achieved after leaving the hand will depend on the actual velocity. Air resistance causes some of this energy to be lost to the air as frictional dissipation, which warms the air in the area as well as the ball's surface.

We can just talk about how the ball moves when it is in the gravitational field of the Earth if we ignore this for the purposes of this discussion. The ball's total energy as it is released is comprised of both its gravitational potential energy and its kinetic energy, which result from the ball's velocity (due to its position).

The gravitational potential energy begins to rise as the ball moves vertically upward at precisely the same pace as it loses kinetic energy. The ball experiences a steady downward acceleration of 9.81 m/s2, which causes it to initially decline until it briefly comes to a stop at its highest point.

Due to its current position in the Earth's gravitational field relative to its initial position, all of the energy at this point is gravitational potential energy. As the ball experiences constant downward acceleration, its motion immediately becomes apparent in that direction because the acceleration easily transforms gravitational potential energy back into kinetic energy.

As a result, at every point along the trajectory, the total of these interchangeable forms of energy remains constant.

To learn more about what happens when a ball is thrown vertically upward:

brainly.com/question/1121850

3 0
1 year ago
The law of conservation of matter states that during a chemical reaction
Sveta_85 [38]
This law states that, despite chemical reactions or physical transformations, mass is conserved — that is, it cannot be created or destroyed — within an isolated system
4 0
4 years ago
A wave has a wavelength of 10mm and a frequency of 5 hz what is the speed?
geniusboy [140]
V=fλ
v=5*0.01
Therefore v=0.05
3 0
4 years ago
Read 2 more answers
Ag,Au and Cu are called coinage metals why plzzzz hurry its urgent plzzz​
Ronch [10]

Answer:

This is because these metals are used for minting (making) coins.

8 0
3 years ago
A fan that is rotating at 960 rev/s is turned off. It makes 1500 revolutions before it comes to a stop. a) What was its angular
Evgesh-ka [11]

Answer:

α = 1930.2 rad/s²

Explanation:

The angular acceleration can be found by using the third equation of motion:

2\alpha \theta=\omega_f^2-\omega_i^2

where,

α = angular acceleration = ?

θ = angular displacement = (1500 rev)(2π rad/1 rev) = 9424.78 rad

ωf = final angular speed = 0 rad/s

ωi = initial angular speed = (960 rev/s)(2π rad/1 rev) = 6031.87 rad/s

Therefore,

2\alpha(9424.78\ rad) = (0\ rad/s)^2-(6031.87\ rad/s)^2\\\\\alpha = -\frac{(6031.87\ rad/s)^2}{(2)(9424.78\ rad)}

<u>α = - 1930.2 rad/s²</u>

<u>negative sign shows deceleration</u>

5 0
4 years ago
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