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4 years ago

Which term describes the sum of all forces acting on an object

Physics

2 answers:

OlgaM077 [116]4 years ago

7 0

Answer:

<em>The sum of all the forces acting on an object is the net force or resultant force. ... For example, gravitational force (on earth) acts in downward direction and has a magnitude equal to mass of the object and acceleration due to gravity.</em>

Explanation:

viva [34]4 years ago

4 0

That's the <em>Net Force</em> on the object.

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oksano4ka [1.4K]

Answer:

<h2>Radiation</h2>

Explanation:

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3 years ago

How does the law of conservation of mass apply to this reaction: Mg + HCl → H2 + MgCl2?

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3 years ago

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Determine whether each of the following combinations of forces can be in equilibrium if their directions

lesya692 [45]

Answer:

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3 years ago

What is the mathematical expression for the electric ptential difference between points A and B when a charged particle is movin

ratelena [41]

Answer:

$chang in V=\int\limits^B_A {E} \, ds$

Explanation:

Since, as we know, the potential difference 'ΔV' is the difference of between the Potential energy per unit charge U/qo at one point 'B' to Potential energy per unit charge at other point 'A'. It so happens when a test charge 'qo' moves from point A to B, the potential difference becomes the change of potential energy of the system, i.e.

$Potential Difference =\frac{change in U}{qo}=\int\limits^B_A {E} \, ds$

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3 years ago

A wagon is rolling forward on level ground. Friction is negligible. The person sitting in the wagon is holding a rock. The total

Rudik [331]

Answer:

a) 0.41 m/s

b) 0.51 m/s

Explanation:

(a)

M = total mass of wagon, rider and the rock = 93.1 kg

V = initial velocity of wagon = 0.456 m/s

m = mass of the rock = 0.292 kg

v = velocity of rock after throw = 15.4 m/s

V' = velocity of wagon after rock is thrown

Using conservation of momentum

M V = m v + (M - m) V'

(93.1) (0.456) = (0.292) (15.4) + (93.1 - 0.292) V'

V' = 0.41 m/s

M = total mass of wagon, rider and the rock = 93.1 kg

V = initial velocity of wagon = 0.456 m/s

m = mass of the rock = 0.292 kg

v = velocity of rock after throw = - 15.4 m/s

V' = velocity of wagon after rock is thrown

Using conservation of momentum

M V = m v + (M - m) V'

(93.1) (0.456) = (0.292) (- 15.4) + (93.1 - 0.292) V'

V' = 0.51 m/s

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4 years ago