Answer: YES !!
Explanation: THAT WOULD BE AMAZING!!!
Answer:
Decreases the time period of revolution
Explanation:
The time period of Cygnus X-1 orbiting a massive star is 5.6 days.
The orbital velocity of a planet is given by the formula,
v = √[GM/(R + h)]
In the case of rotational motion, v = (R +h)ω
ω = √[GM/(R + h)] /(R +h)
Where 'ω' is the angular velocity of the planet
The time period of rotational motion is,
T = 2π/ω
By substitution,
<em>T = 2π(R +h)√[(R + h)/GM] </em>
Hence, from the above equation, if the mass of the star is greater, the gravitational force between them is greater. This would reduce the time period of revolution of the planet.
R=U/I so
U=RxI
U= 10 x 42
U= 420 volts
Answer:

Explanation:
The formula for force is:

If we rearrange the formula to solve for a (acceleration), the formula becomes

The force is 68 Newtons. Let's convert the units to make the problem easier later on. 1 N is equal to 1 kg*m/s², so the force of 68 N is equal to 68 kg*m/s².
The mass is 2 kilograms.

Substitute the values into the formula.

Divide. Note that the kilograms will cancel each other out (hence why we changed the units).


The acceleration is<u> </u><u>34 meters per second squared.</u>