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r-ruslan [8.4K]
4 years ago
15

What are the main causes of the convention currents in the asthenosphere?

Physics
2 answers:
Tju [1.3M]4 years ago
8 0
I think it is c density and temperature
Verizon [17]4 years ago
6 0

Answer:

It c

Explanation:

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The sound travels _______ in liquid as compare to solid
LenaWriter [7]

Answer:

in mechanical waves

Explanation:

A mechanical wave is a disturbance that moves and transports energy from one place to another through a medium. In sound, the disturbance is a vibrating object. And the medium can be any series of interconnected and interactive particles.

7 0
3 years ago
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Newton's "quantity of motion" is conservation.<br><br> True<br><br> False
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The answer is false hope this helps
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Which term describes an area of low density in a longitudinal wave?
LiRa [457]

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Explanation:

Low density is an area of rarefaction.

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Please HEEEEELPPPP !!!!!
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5 0
3 years ago
Calculate the acceleration of a skier heading down a 10.0º slope, assuming the coefficient of friction for waxed wood on wet sno
lutik1710 [3]

(a) 0.74 m/s^2

Explanation:

There are two forces acting on the skier: the component of the weight parallel to the slope, which acts downward, and the frictional force, which acts upward along the incline.

The component of the weight parallel to the inclined plane is:

W= m g sin \theta

where m is the mass of the skier, g=9.81 m/s^2 and \theta=10^{\circ}.

The frictional force is instead

F_f = -\mu m g cos \theta

\mu=0.1 is the coefficient of friction for waxed wood on wet snow.

If we apply Newton's second law, we can write that the net force must be equal to the product of mass per acceleration:

mgsin \theta -\mu mg cos \theta =ma

And symplifying m, we can find the acceleration:

a=g sin \theta-\mu g cos \theta=

=(9.81 m/s^2)(sin 10^{\circ})-(0.1)(9.81 m/s^2)(cos 10^{\circ})=0.74 m/s^2


(b) 5.7^{\circ}

Explanation:

This time, the skier is moving at constant velocity. Therefore, the acceleration is zero (a=0) and Newton's second law becomes:

mg sin \theta - \mu m g cos \theta=0

By simplifying, we get

tan \theta = \mu

From which we can find the angle at which the skier could coast at a constant velocity:

\theta= tan^{-1} (\mu) = tan^{-1} (0.1)=5.7^{\circ}



6 0
3 years ago
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