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Rina8888 [55]
3 years ago
7

Write the following expression as a single logarithm with coefficient 1. log910 − log9 1 2 − log94

Mathematics
2 answers:
sesenic [268]3 years ago
8 0

Answer:

its a

Step-by-step explanation:

nikitadnepr [17]3 years ago
6 0

The answer is A. Log 9 5

I got it right on ed .

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Using Order of Operations (PEMDAS), solve the following two expressions. Show all steps.
aksik [14]

Answer:

A:

Multiple: 3 * 5 = 15

Add: 7 + the result of step No. 1 = 7 + 15 = 22

Divide: 4 / 2 = 2

Subtract: the result of step No. 2 - the result of step No. 3 = 22 - 2 = 20

Add: the result of step No. 4 + 3 = 20 + 3 = 23

B:

Add: 7 + 3 = 10

Multiple: the result of step No. 1 * 5 = 10 * 5 = 50

Divide: 4 / 2 = 2

Subtract: the result of step No. 2 - the result of step No. 3 = 50 - 2 = 48

Add: the result of step No. 4 + 3 = 48 + 3 = 51

8 0
2 years ago
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Help mewa plzzzzzzzz
Sophie [7]

Answer:

It has the same shape and angels as a trapezoid therefor it is a trapezoid

Step-by-step explanation: If u dont believe me, look for a pic of a trapezoid on google

8 0
3 years ago
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40 POINTS!!!! ANSWER CORRECTLY PLZ
Grace [21]

Answer:

5. ○ \displaystyle \frac{25}{48}

4. ○ \displaystyle \frac{25}{46}

3. ○ \displaystyle \frac{31}{100}

2. ○ \displaystyle \frac{3}{4}

1. ○ \displaystyle \frac{27}{50}

Step-by-step explanation:

5. \displaystyle \frac{25}{23 + 25} = \frac{25}{48}

4. \displaystyle \frac{25}{46} = \frac{25}{21 + 25}

3. \displaystyle Flat-out\:given\:to\:you

2. \displaystyle \frac{21 + 23 + 31}{100} = \frac{75}{100} = \frac{3}{4}

1. \displaystyle \frac{31 + 23}{100} = \frac{54}{100} = \frac{27}{50}

I am joyous to assist you anytime.

7 0
3 years ago
How would you write 62.22 in expanded form
BARSIC [14]
All you have to do is to solve this problem is 60+2+0.20+0.02
3 0
3 years ago
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Hem dibuixat tres rectangles. En el primer, la llargada mesura 3 cm més que l'amplada. El segon i tercer rectangle tenen unes di
quester [9]

Resposta:

Primer rectangle:

Amplada = 11

Longitud = 14

Segon rectangle:

Amplada = 12

Longitud = 15

Tercer rectangle:

Amplada = 13

Longitud = 16

Explicació pas a pas:

Donat que:

Primer rectangle:

Amplada = x

Longitud = x + 3

2n rectangle:

Augment de la dimensió d'1 cm respecte al primer rectangle;

Amplada = x + 1

Longitud = x + 4

3r rectangle:

Augment de la dimensió de 2 cm respecte al primer rectangle;

Amplada = x + 2

Longitud = x + 5

Suma dels tres perímetres del rectangle:

Perímetre d'un rectangle: 2 (l + O)

Primer rectangle:

2 (x + x + 3) = 2 (2x + 3) = 4x + 6

2n:

2 (x + 1 + x + 4) = 2 (2x + 5) = 4x + 10

3r:

2 (x + 2 + x + 5) = 2 (2x + 7) = 4x + 14

Suma de perímetres = 162

(4x + 6 + 4x + 10 + 4x + 14) = 162

12x + 30 = 162

12x = 162 - 30

12x = 130

x = 11

Per tant,

Primer rectangle:

Amplada = 11

Longitud = 11 + 3 = 14

2n rectangle:

Amplada = 11 + 1 = 12

Longitud = 11 + 4 = 15

3r rectangle:

Amplada = 11 + 2 = 13

Longitud = 11 + 5 = 16

8 0
3 years ago
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