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AnnyKZ [126]
3 years ago
9

Determine the reagents needed and the synthetic intermediate that is formed in the conversion of the secondary alcohol into the

cyanohydrin given below. drag the appropriate labels to their respective targets.

Chemistry
1 answer:
astra-53 [7]3 years ago
5 0
Secondary Alcohol is converted into corresponding Cyanohydrin in two steps;

Step 1:
           Oxidation of Sec. Alcohol:
                                                    Secondary Alcohols when treated with Sodium Dichromate in acidic medium are converted into corresponding Ketone.

Step 2:
           Reduction of Ketone using HCN:
                                                               Ketone is reduced to Cyaynohydrin when treated with CN nucleophile. A nucleophillic addition reaction takes place.

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How many moles of water are produced if 5.43 mol PbO2 are consumed?<br><br> ANSWER: 10.9
Arada [10]

Answer: 10.9 mol.

Explanation:

  • To understand how to solve this problem, we must mention the reaction equation where water produced from PbO₂.

Pb + PbO₂ + 2H₂SO₄ → 2PbSO₄ + 2H₂O

  • Now, it is a stichiometric oriented problem, that 1 mole of PbO₂ produces 2 moles of H₂O.

Using cross multiplication:

1.0 mole of PbO₂ → 2.0 moles of H₂O

5.43 moles of PbO₂ → ??? moles of water

The moles of water produced = (5.43 x 2.0) = 10.86 moles ≅ 10.9 moles.

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3 years ago
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marin [14]
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5 0
3 years ago
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How many moles of atoms are contained in 15.7 g of Bromine
Vlada [557]
1 mol of Br = 79.9 g

15.7 g / 79.9 g = 0.196 moles of atoms
3 0
3 years ago
n a gas-phase equilibrium mixture of SbCl5, SbCl3, and Cl2 at 500 K, pSbCl5 = 0.17 bar and pSbCl3 = 0.22 bar. Calculate the equi
Lorico [155]

Answer:

2.7 × 10⁻⁴ bar

Explanation:

Let's consider the following reaction at equilibrium.

SbCl₅(g) ⇄ SbCl₃(g) + Cl₂(g)

The pressure equilibrium constant (Kp) is 3.5 × 10⁻⁴. We can use these data and the partial pressures at equilibrium of SbCl₅ and SbCl₃, to find the partial pressure at equilibrium of Cl₂.

Kp = pSbCl₃ × pCl₂ / pSbCl₅

pCl₂ = Kp × pSbCl₅ / pSbCl₃

pCl₂ = 3.5 × 10⁻⁴ × 0.17 / 0.22

pCl₂ = 2.7 × 10⁻⁴ bar

7 0
3 years ago
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