Determine the reagents needed and the synthetic intermediate that is formed in the conversion of the secondary alcohol into the
cyanohydrin given below. drag the appropriate labels to their respective targets.
1 answer:
Secondary Alcohol is converted into corresponding Cyanohydrin in two steps;
Step 1:
Oxidation of Sec. Alcohol:
Secondary Alcohols when treated with Sodium Dichromate in acidic medium are converted into corresponding Ketone.
Step 2:
Reduction of Ketone using HCN:
Ketone is reduced to Cyaynohydrin when treated with CN nucleophile. A nucleophillic addition reaction takes place.
Step 1:
Oxidation of Sec. Alcohol:
Secondary Alcohols when treated with Sodium Dichromate in acidic medium are converted into corresponding Ketone.
Step 2:
Reduction of Ketone using HCN:
Ketone is reduced to Cyaynohydrin when treated with CN nucleophile. A nucleophillic addition reaction takes place.
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Complete Question
The complete question is shown on the first uploaded image
Answer:
a) Splitting pattern for Ha= 2+1 , Triplet
For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3
Splitting pattern for Hb and Hc= 3+1 , Quartet
For Proton Hd, number of non equivalent protons n= 0
Splitting pattern for Hd= 0+1 , Singlet
b) Splitting pattern for Ha= 2+1 , Triplet
For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3
Splitting pattern for Hb and Hc= 3+1 , Quartet
For Proton Hd, number of non equivalent protons n= 0
Splitting pattern for Hd= 0+1 , Singlet
c) The IUPAC name is Butan-2-ol
Explanation:
Considering the first question the rule used for prediction of splitting pattern is n+1 (Pascal's Triangle rule), where n is number of H atom on the adjacent carbon which are non equivalent.
According to that for molecule 1 as shown on the second uploaded image
For Proton Ha, number of non equivalent protons n= 2
Splitting pattern for Ha= 2+1 , Triplet
For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3
Splitting pattern for Hb and Hc= 3+1 , Quartet
For Proton Hd, number of non equivalent protons n= 0
Splitting pattern for Hd= 0+1 , Singlet
Considering the second question for Molecule 2 as shown on the third uploaded image
For Proton Ha, number of non equivalent protons n= 1
Splitting pattern for Ha= 1+1=2 , Doublet
For Proton Hb, number of non equivalent protons n= 3
Splitting pattern for Hb= 3+1=4 , Quartet
For Proton Hc, number of non equivalent protons n= 3
Splitting pattern for Hc= 3+1=4 , Quartet
For Proton Hd, number of non equivalent protons n= 1
Splitting pattern for Ha= 1+1=2 , Doublet
Considering the third question
The name of the given molecule is gotten according to longest carbon chain = 4 (Prefix 'Butan')
Functional group = -OH (Suffix 'ol') at C-2
The IUPAC name is Butan-2-ol
Answer:
The right response is "6 A". A further explanation is given below.
Explanation:
The given values are:
Resistance,
R = 6 ohms
Voltage,
V = 36 volts
As we know,
⇒
then,
⇒
On substituting the values, we get
⇒
⇒