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Damm [24]
3 years ago
14

I need help with this question I'm stuck please help !

Mathematics
1 answer:
sertanlavr [38]3 years ago
7 0
Evaluate<span> the series by expanding the summation, then adding all of the values. 154 would be the answer.</span>
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Needs help answering
konstantin123 [22]

Answer:

26

Step-by-step explanation:

the answer is 26

6 0
2 years ago
Can someone help me with these questions and show work please and thank you
attashe74 [19]

Answer:

11. 78

12. 4x² - 3x - 1

Step-by-step explanation:

11. Sum of n whole numbers = ½(n² + n)

Multiply

½*n² + ½*n

= n²/2 + n/2

To find the sum of the first 12 whole number, substitute 12 for n into the equation.

= 12²/2 + 12/2

= 144/2 + 12/2

= 72 + 6

= 78

12. Area of trapezoid = ½(a + b)*h

Where,

a = 5x - 4

b = 3x + 2

h = x + 1

Area = ½(5x - 4 + 3x + 2)*(x + 1)

Area = ½(8x - 2)*(x + 1)

Area = ½[8x(x + 1) -2(x + 1)]

= ½[8x² + 8x - 2x - 2]

Add like terms

= ½(8x² - 6x - 2)

= ½(8x²) - ½(6x) - ½(2)

= 4x² - 3x - 1

6 0
3 years ago
Hey! i need help plz
tia_tia [17]
X=6 and y=-9. Not sure if y is correct since I kind of rushed but I hope this helps!
6 0
3 years ago
tina's family buys 4 cheeseburges and three order of fries for $7.25. Louise's family buys 6 cheeseburgers and 3 orders of fries
nexus9112 [7]
It is 1.25 for 1 hamburger and .75 for fries. Sorry if it’s wrong but hope I helped!!
4 0
3 years ago
A square is inscribed in a circle of diameter 12 millimeters. What is the area of the shaded region? A square is inscribed in a
bezimeni [28]

Answer:  A. (72π - 144) mm²

<u>Step-by-step explanation:</u>

A_{shaded}=A_{circle}-A_{square}\\\\\\A_{circle}=\pi \cdot r^2\\.\qquad \ =\pi \bigg(\dfrac{12\sqrt2}{2}\bigg)^2\\\\.\qquad \ =\pi (6\sqrt2)^2\\.\qquad \ =72\pi\\\\\\A_{square}=side^2\\.\qquad \quad =\dfrac{12\sqrt2}{\sqrt2}^2\\\\.\qquad \quad =12^2\\\\.\qquad \quad =144\\\\\\\large\boxed{A_{shaded}=72\pi-144}

7 0
3 years ago
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