Answer:
is the required equation.
Therefore, the second option is true.
Step-by-step explanation:
We know that the slope-intercept form of the line equation of a linear function is given by
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
where m is the slope and b is the y-intercept
Taking two points (0, -2) and (1, 0) from the table to determine the slope using the formula
![\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=%5Cmathrm%7BSlope%7D%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
![\left(x_1,\:y_1\right)=\left(0,\:-2\right),\:\left(x_2,\:y_2\right)=\left(1,\:0\right)](https://tex.z-dn.net/?f=%5Cleft%28x_1%2C%5C%3Ay_1%5Cright%29%3D%5Cleft%280%2C%5C%3A-2%5Cright%29%2C%5C%3A%5Cleft%28x_2%2C%5C%3Ay_2%5Cright%29%3D%5Cleft%281%2C%5C%3A0%5Cright%29)
![m=\frac{0-\left(-2\right)}{1-0}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B0-%5Cleft%28-2%5Cright%29%7D%7B1-0%7D)
![m=2](https://tex.z-dn.net/?f=m%3D2)
substituting the point (0, -2) and the slope m=2 in the slope-intercept form to determine the y-intercept i.e. 'b'.
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
![-2 = 2(0)+b](https://tex.z-dn.net/?f=-2%20%3D%202%280%29%2Bb)
![-2=0+b](https://tex.z-dn.net/?f=-2%3D0%2Bb)
![b=-2](https://tex.z-dn.net/?f=b%3D-2)
Now, substituting the values of m=2 and b=-2 in the slope-intercept form to determine the equation of a linear function
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
![y=2x+(-2)](https://tex.z-dn.net/?f=y%3D2x%2B%28-2%29)
![y=2x-2](https://tex.z-dn.net/?f=y%3D2x-2)
Thus,
is the required equation.
Therefore, the second option is true.