Use the method of completing the square to transform the quadratic equation into the equation form (x – p)^2 = q.
1 answer:
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You can solve this problem by folllowing the steps below:
1. Draw a segment from the point C to the line AE, as you can see in the figure attached.
2. You have now two equal right trapezoids, then: m∠ABG=m∠EDG.
3. m∠ACE=m∠EDG
3. The sum of the interior angles of the trapezoid is 360º.
4. Then, you have:
m∠EDG+m∠D+m∠G+m∠F=360º
m∠D=115º
m∠G=90º
m∠F=90º
5. When you clear m∠EDG, you obtain:
m∠EDG=360º-m∠D-m∠G-m∠F
m∠EDG=360º-115º-90º-90º
m∠EDG=65º
6. Therefore:
m∠ACE=m∠EDG
m∠ACE=65º
The answer is: C.65º
1. Draw a segment from the point C to the line AE, as you can see in the figure attached.
2. You have now two equal right trapezoids, then: m∠ABG=m∠EDG.
3. m∠ACE=m∠EDG
3. The sum of the interior angles of the trapezoid is 360º.
4. Then, you have:
m∠EDG+m∠D+m∠G+m∠F=360º
m∠D=115º
m∠G=90º
m∠F=90º
5. When you clear m∠EDG, you obtain:
m∠EDG=360º-m∠D-m∠G-m∠F
m∠EDG=360º-115º-90º-90º
m∠EDG=65º
6. Therefore:
m∠ACE=m∠EDG
m∠ACE=65º
The answer is: C.65º
9514 1404 393
Answer:
185°
Step-by-step explanation:
The triangle internal angle at Y is 145° -45° = 100°. Since the triangle is isosceles, the internal angles at X and Z are both (180° -100°)/2 = 40°. Then the bearing of Z from X is the bearing of Y from X less the internal angle at X:
(45° +180°) -40° = 185°.
Z from X is 185°.
