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4 years ago

Show how 3 4 × 4 can be solved using repeated addition.

Mathematics

1 answer:

polet [3.4K]4 years ago

7 0

Answer: $34*4=34+34+34+34=136$

Step-by-step explanation:

In order to solve this exercise it is important to remember that the "Repeated addition" is about adding equal groups of numbers.

Therefore, you can solve a mulitplication using the Repeated addition by repeat the same number "n" times in order to find the result..

In this case, you have the following multiplication given in the exercise:

$34*4$

You can observe that the number 34 is multiplied by 4. This indicates that the result is four times 34.

Then, based on the explained at the beginning of this explanation, you can conclude that you can also solve the given multiplication by repeating the number 34 four times and then adding the groups.

Therefore, you get:

$34*4=34+34+34+34=136$

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Simplifying $\left(x^2+8xy+16y^2\right)^{\frac{1}{3}}.\left(x+4y\right)^{\frac{1}{3}}$ we get $\left(x+4y\right)}$

Step-by-step explanation:

We need to simplify:

$\left(x^2+8xy+16y^2\right)^{\frac{1}{3}}.\left(x+4y\right)^{\frac{1}{3}}$

For solving, we will first simplify the terms inside the exponent and then solve exponent

First Solving: $\left(x^2+8xy+16y^2\right)}.\left(x+4y\right)}$

Using the formula: $(a^2+2ab+b^2)=(a+b)^2$

$\left(x^2+8xy+16y^2\right)}.\left(x+4y\right)}\\\left((x)^2+2(x)(4y)+(4y)^2\right)}.\left(x+4y\right)}\\\left(x+4y\right)^2}.\left(x+4y\right)}$

Using exponent rule:

$a^m.a^n=a^{m+n}$

$\left(x+4y\right)^{2+1}}\\\left(x+4y\right)^3}$

Now,

$(\left(x+4y\right)^3})^{\frac{1}{3}}\\Simplifiying:\\\left(x+4y\right)}^{\frac{3}{3}}\\\left(x+4y\right)}$

So, simplifying $\left(x^2+8xy+16y^2\right)^{\frac{1}{3}}.\left(x+4y\right)^{\frac{1}{3}}$ we get $\left(x+4y\right)}$

Keywords: Solving Rational exponents:

Learn more about Solving Rational exponents at:

#learnwithBrainly

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