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Akimi4 [234]
3 years ago
10

Show how 3 4 × 4 can be solved using repeated addition.

Mathematics
1 answer:
polet [3.4K]3 years ago
7 0

Answer:  34*4=34+34+34+34=136

Step-by-step explanation:

In order to solve this exercise it is important to remember that the  "Repeated addition" is about adding equal groups of numbers.

Therefore, you can solve a mulitplication using the Repeated addition by repeat the same number "n" times in order to find the result..

In this case, you have the following multiplication given in the exercise:

34*4

You can observe that the number 34 is multiplied by 4. This indicates that the result is four times 34.

Then, based on the explained at the beginning of this explanation, you can conclude that you can also solve the given multiplication by repeating the number 34 four times and then adding the groups.

Therefore, you get:

34*4=34+34+34+34=136

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Select all the correct expressions in the table which expressions are equivalent to the given complex number 45+2i
aksik [14]

Answer:

its gonna be the second one down on the left!! i can give an explanation if ur having trouble

Step-by-step explanation:

6 0
3 years ago
87 ÷ 17 + [672 - 83] another one
never [62]

Answer:

594.1

Step-by-step explanation:

87÷15=5.1

672-83=589

so then you add those to together and get 594.1

3 0
3 years ago
Substitution method for 7x-2y=1 & x-2y=1
RUDIKE [14]
We want to use the Substitution method to solve
7x - 2y = 1          (1)
x - 2y = 1           (2)

From equation (1), obtain
2y = 7x - 1          (3)

Substitute (3) into (2).
x - (7x - 1) = 1
-6x + 1 = 1
-6x = 0
x = 0

From (3), obtain
2y = 7*0 - 1 = -1
y = -1/2

Answer: (0, -1/2)  or x=0, y= -1/2.

6 0
3 years ago
Which numbers in Set A = {−7, −4, 2, 14, 21, 34, 42} are elements of both Set B and Set C, shown below? Set B = {even numbers} S
sweet [91]

Answer:

14, 42

Step-by-step explanation:

Set A = {−7, −4, 2, 14, 21, 34, 42}

Set B = {even numbers}

Set C = {multiples of 7}

There is only one question asked

Which numbers in Set A are elements of both Set B and Set C,

We need it to be even and a multiple of 7

14 is even and a multiple of 7  and 42 is even and a multiple of 7

5 0
3 years ago
Read 2 more answers
It takes 300 newtons of force and a distance of 20 meters for a moving car to come to stop. How much work is a one n the cart?
IceJOKER [234]
Work done on cart
:

W
=
6000

J
Kinetic energy of cart
:

E
K
=
6000

J
Explanation:
Work done
W
is defined as the product of force
F
and distance
s
:
⇒
W
=
F
⋅
s
Let's substitute the values of
F
and
s
into the equation:
⇒
W
=
300

N

⋅
20

m
⇒
W
=
300

kg

⋅

m s
−
2

⋅
20

m
⇒
W
=
300
⋅
20

kg

⋅

m
2

s
−
2
⇒
W
=
6000

kg

⋅

m
2

s
−
2
∴
W
=
6000

J
The gain in kinetic energy
E
K
is the same amount as the work done moving the cart:
∴
E
K
=
6000
7 0
3 years ago
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