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ipn [44]
3 years ago
6

What happens during exhalation ?

Biology
1 answer:
Anvisha [2.4K]3 years ago
8 0
During forced <span>exhalation</span>, as when blowing out a candle, expiratory muscles including the abdominal muscles and internal intercostal muscles generate abdominal and thoracic pressure, which forces air out of the lungs.
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Channels allow the appropriate ions or small molecules to pass through.<br> (a) True<br> (b) False
denis23 [38]

Answer:

The given statement is true.

Explanation:

A channel protein refers to a protein, which permits the conduction of particular substances like small molecules or ions through the cell membrane. They perform this task either through the process of active transport or facilitated diffusion on the basis of the concentration gradient or due to the variation in the concentration of components outside and within the cell membrane.

5 0
3 years ago
If the frequency of the recessive allele for a gene is 0.3, calculate the expected frequency of heterozygotes in the next genera
Kisachek [45]
Q = recessive allele frequency = 0.3, and thus in H-W equilibrium there are ONLY two alleles, q (recessive) and
p (dominant). Therefore all of the p and q present for this gene in a population must account for 100% of this gene's alleles. And 100% = 1.00.
So p, the dominant allele frequency, must be equal to 1 - q --> p = 1 - q
p = 1 - 0.3 = 0.7.
Since heterozygotes are a combination of the p and q, we must again look at the frequencies of each genotype: p + q = 1, then (p+q)^2 = 1^2
So multiplying out (p+q)(p+q) = 1, we get: p^2+2pq+q^2 = 1 (all genotypes), where p^2 = frequency of homozygous dominant individuals, 2pq = frequency of heterozygous individuals, and q^2 = frequency of homozygous recessive individuals.
Therefore if the population is in H-W equilibrium, then the expected frequency of heterozygous individuals = 2pq = 2(0.7)(0.3)
2pq = 2(0.21) = 0.42, or 42% of the population.
Hope that helps you to understand how to solve population genetics problems!
7 0
3 years ago
As oceanic lithosphere bends and is pulled underneath another plate, what is formed?
pantera1 [17]
I believe the answer is a deep oceanic trench. Hope this helped! <3
7 0
2 years ago
Need help will mark Brainliest
ludmilkaskok [199]

Answer:

C

Explanation:

Semiconservative replication means that strand will also be used. (Pretty sure)

6 0
3 years ago
In fast-twitch oxidative-glycolytic fibers, their rapid increases in force rely on the ________ activity where rapid relaxation
Kitty [74]

Answer:

1. myosin ATPase

2. Ca2+-ATPase

Explanation:

ATPase activity of myosin head hydrolysis ATP and energize the myosin head. The energized myosin head forms cross bridges to facilitate the power stroke of muscle contraction. The fast-twitch oxidative-glycolytic fibers have the ability to produce ATP by aerobic respiration.  

These fibers have the  ATPase in their myosin heads that hydrolyze ATP three to five times faster than the myosin ATPase in slow fibers. This ensures the faster speed of contraction of these fast-twitch muscle fibers.

During their relaxation, Ca2+ ATPase pumps the calcium ions back to the sarcoplasmic reticulum. As the level of Ca2+ ions in the sarcoplasm decreases, calcium ions are released from troponin. Tropomyosin is allowed to cover the myosin-binding sites on actin and the muscle fiber relaxes faster.

4 0
2 years ago
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