Answer:
Multiple answers:
1. Power output P=17.59W
2.Intensity 160m I=17.6W/
3. dB = 77.3
4. f=178.5 Hz
Explanation:
First one comes from the expression

where<em> I </em>is the intensity, <em>P </em>is the power and <em>r </em>is the radio of the spherical wave, or in this case, the distance <em>x</em>. I solved for the Power by multiplying Intensity with the area (4
Second one is done with:

Solving for Intensity 2, the result mentioned.
The third is simply computed with

And finally the last one is done with doppler effect, taking into account the speed of the air as in 10ºC 337m/s.

Where <em>Finitial</em> is the frequency emitted and <em>s</em> is the speed of the sound. The wind blowing in positive is, in principle, going away of the observer.
Answer:
(A)
Explanation:
P1 = MVcos 30
P2 = MVcos 30
️P = -2 mvcos 30
️P = - square root of 3 mv
f1 = 2mv/ ️t
force on the wall = 2
f2 = square root of 3mv/ ️t, so f1 > f2
Explanation:
Significant figures of a number written in positional notation are digits that carry meaningful contributions to the measurement resolution of the number.
Answer:
Neither both are correct
Explanation:
The question involves the removal and installation procedure of cable for parking break. The answer for this could be found through the manual procedure for repairing parking break
Technician A is wrong because rear brakes should be adjusted before the parking cable adjustment is being made.
Technician B is wrong because the parking brake lever should be intact and secure at all clicks to allow maximum security. 15 clicks in this case should be the maximum number of clicks for the lever.
Answer:
Magnetic field at point having a distance of 2 cm from wire is 6.99 x 10⁻⁶ T
Explanation:
Magnetic field due to finite straight wire at a point perpendicular to the wire is given by the relation :
......(1)
Here I is current in the wire, L is the length of the wire, R is the distance of the point from the wire and μ₀ is vacuum permeability constant.
In this problem,
Current, I = 0.7 A
Length of wire, L = 0.62 m
Distance of point from wire, R = 2 cm = 2 x 10⁻² m = 0.02 m
Vacuum permeability, μ₀ = 4π x 10⁻⁷ H/m
Substitute these values in equation (1).

B = 6.99 x 10⁻⁶ T