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andrey2020 [161]
3 years ago
6

Brainliest if right.

Physics
1 answer:
jeka57 [31]3 years ago
5 0

Answer:

the third law (for every action there is an equal and opposite reaction).

Explanation:

The skateboarder pushes backwards on the road (that is he applies a force on the road in a direction opposite the direction of intended motion). By Newton's third law, this action of the skateboarder causes an equal reaction of the road on the skateboarder in the opposite direction. Newton's third law states that action and reaction are equal but opposite in direction. So, the road in response to this backward force pushes the skateboarder in the forward direction causing the skateboarder and the skateboard to move in the forward direction.

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A point source at the origin emits sound of frequency 175 Hz uniformly in all directions. On the x-axis at x=100 m, the sound in
hammer [34]

Answer:

Multiple answers:

1. Power output P=17.59W

2.Intensity 160m I=17.6W/m^{2}

3. dB = 77.3

4. f=178.5 Hz

Explanation:

First one comes from the expression

I=\frac{P}{4\pi r^{2} }

where<em> I </em>is the intensity, <em>P </em>is the power and <em>r </em>is the radio of the spherical wave, or in this case, the distance <em>x</em>. I solved for the Power by multiplying Intensity with the area (4\pi x^{2}

Second one is done with:

\frac{I_{2} }{I_{1} } =\frac{x^{2}_{1} }{x^{2} _{2}}

Solving for Intensity 2, the result mentioned.

The third is simply computed with

dB=10*log\frac{I}{10^{-12} }

And finally the last one is done with doppler effect, taking into account the speed of the air as in 10ºC 337m/s.

f=f_{initial} *(\frac{s+v_{receiver} }{s+v_{source} } )

Where <em>Finitial</em> is the frequency emitted and <em>s</em> is the speed of the sound. The wind blowing in positive is, in principle, going away of the observer.

8 0
3 years ago
Solve this question and give to a detailed step-by-step process as to how you got the answer. Thanks in advance!
m_a_m_a [10]

Answer:

(A)

Explanation:

P1 = MVcos 30

P2 = MVcos 30

️P = -2 mvcos 30

️P = - square root of 3 mv

f1 = 2mv/ ️t

force on the wall = 2

f2 = square root of 3mv/ ️t, so f1 > f2

6 0
3 years ago
Read 2 more answers
What is significant figures​
Maurinko [17]

Explanation:

Significant figures of a number written in positional notation are digits that carry meaningful contributions to the measurement resolution of the number.

5 0
4 years ago
Read 2 more answers
Technician A says the parking brake cable adjustment should be performed before adjusting the rear brakes. Technician B says the
Firlakuza [10]

Answer:

Neither both are correct

Explanation:

The question involves the removal and installation procedure of cable for parking break. The answer for this could be found through the manual procedure for repairing parking break

Technician A is wrong because rear brakes should be adjusted before the parking cable adjustment is being made.

Technician B is wrong because the parking brake lever should be intact and secure at all clicks to allow maximum security. 15 clicks in this case should be the maximum number of clicks for the lever.

7 0
3 years ago
A straight wire of length 0.62 m carries a conventional current of 0.7 amperes. What is the magnitude of the magnetic field made
anyanavicka [17]

Answer:

Magnetic field at point having a distance of 2 cm from wire is 6.99 x 10⁻⁶ T

Explanation:

Magnetic field due to finite straight wire at a point perpendicular to the wire is given by the relation :

B=\frac{\mu_{0}I }{2\pi R }\times\frac{L}{\sqrt{L^{2}+R^{2}  } }      ......(1)

Here I is current in the wire, L is the length of the wire, R is the distance of the point from the wire and μ₀ is vacuum permeability constant.

In this problem,

Current, I = 0.7 A

Length of wire, L = 0.62 m

Distance of point from wire, R = 2 cm = 2 x 10⁻² m = 0.02 m

Vacuum permeability, μ₀ = 4π x 10⁻⁷ H/m

Substitute these values in equation (1).

B=\frac{4\pi\times10^{-7}\times  0.7 }{2\pi \times0.02 }\times\frac{0.62}{\sqrt{(0.62)^{2}+(0.02) ^{2}  } }

B = 6.99 x 10⁻⁶ T

3 0
3 years ago
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