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ycow [4]
3 years ago
10

What is the linear speed of a point on the equator, due to the earth's rotation?

Physics
1 answer:
kvv77 [185]3 years ago
8 0
The equatorial radius of the earth is
r = 6378 km = 6378 x 10³ m

The earth makes 1 revolution in 24 hours.
The angular velocity is
ω = (2π rad)/(24*3600 s) = 7.2722 x 10⁻⁵ rad/s

The tangential velocity (linear velocity) at a point on the equator is
v = rω
   = (6378 x 10³ m)*(7.2722 x 10⁻⁵ rad/s)
   = 463.8 m/s

Answer: 463.8 m/s

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Answer:

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As per the question:

\theta = 54.6^{\circ}

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Now,

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Linear velocity, v = \sqrt{\frac{gx}{sin2\theta}}

v = \sqrt{\frac{9.8\times 30.1}{sin2\times 54.6}}

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4. O/N 15/P11/Q11
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Answer:

B) 4500 Pa

Explanation:

As pressure is force per unit area,

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