Answer:
335°C
Explanation:
Heat gained or lost is:
q = m C ΔT
where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.
Heat gained by the water = heat lost by the copper
mw Cw ΔTw = mc Cc ΔTc
The water and copper reach the same final temperature, so:
mw Cw (T - Tw) = mc Cc (Tc - T)
Given:
mw = 390 g
Cw = 4.186 J/g/°C
Tw = 22.6°C
mc = 248 g
Cc = 0.386 J/g/°C
T = 39.9°C
Find: Tc
(390) (4.186) (39.9 - 22.6) = (248) (0.386) (Tc - 39.9)
Tc = 335
Explanation :
When an electron jumps from one energy level to another, the energy of atom gets changed.
If a photon gets absorbed, the electron will move to higher energy levels and then fall back to the lower energy levels. Then each time a photon will be absorbed whose energy is given by difference between the initial and final energy levels i.e
In Balmer series, the transition is from higher energy levels to n = 2.
So, the necessary condition for Balmer series is that the electron should be at first excited state or n = 2 level as shown in figure.
The solution would be like this for this specific problem:
T = 2 * pi * sqrt (Length / g)
T = 2 * 31.4 * sqrt
(1.8m / 3.69 m/second2)
T = 4.386142257432951112677107108824
<span>So
if you had a pendulum on Mars that was 1.8 meters long, the period would be
4.4.</span>
Explanation:
Below is an attachment containing the solution.
Here is are by step :) hope this helps
First things first, you want the resultant to be in the direction of the bearing of 105 °. The distance required is irrelevant for question 1.
You want the addition of the wind speed and the planes velocity to equal some resultant in the direction one 105 °. Draw a parallelogram (vector addition) of the resultant (the 100km in direction 105°) and the wind speed. The diagonal that results from the vector addition will equal 240. You only know the angle between the resultant and the wind speed right now (105°).
https://www.geogebra.org/geometry/rbejhvta
What is the angle between the resultant (the direction we want to travel) and the direction the plane will actually go when wind speed is taken into accound???
Law of sines.
You said you have it, so we will continue under the assumption you got 4.617°.
now, take into account that the plane is accelerating 4.617° off of the 105° bearing in order to travel on the 105° bearing when wind speed is taken into account... what heading is the plane taking? 105° - 4.617° = 100.4°
There is part 1.
now you simply need to find the actual speed she is travelling along the bearing 105°. (she is traveling 240km/h with a 100.4° heading, find the correct speed for the resultant).
EDIT: The representation says 105.1°, it is supposed to say 105°