Question

A 5.0-V battery is places in series with two 1.25-Ω resistors. Determine the current through each resistor.

Answer 1

Answer:

Current through each resistor is 2 A.

Explanation:

Given that,

Voltage of a battery, V = 5 volts

Resistance 1, R = 1.25 ohms

Resistance 2,R' = 1.25 ohms

Both resistors are connected in series. The equivalent resistance is given by :

R" = R + R'

R" = 1.25 + 1.25

R" = 2.5 ohms

The current flowing throughout all resistors is same in series combination of resistors. Current can be calculated using Ohm's law as :

$I=\dfrac{V}{R"}$

$I=\dfrac{5\ V}{2.5}$

I = 2 A

So, the current through each resistor is 2 A. Hence, this is the required solution.