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PSYCHO15rus [73]
3 years ago
11

Spiders kan swim???????

Physics
2 answers:
emmasim [6.3K]3 years ago
4 0

Answer:

some can others will drown.

Explanation:

Nastasia [14]3 years ago
3 0

Answer:

Spiders cannot actually propel their bodies through the water as a swimmer does, but they can use objects to get across the water and some can run across the water.

Explanation:

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What kind of radiation is emitted in the following nuclear reaction
miv72 [106K]

Beta emission is occurring in the given nuclear reaction.

Answer: Option B

<u>Explanation:</u>

In this equation, the reactant is the Thorium atom, which is reduced to palladium. As the atomic number get decreased by one, so an electron will be emitted. This process of emission of electrons by radiation or decaying the reactant nuclei to form a new product nuclei is termed as beta emission.

So, the electrons are generally termed as beta particles while the positrons are termed as positive beta particles. So this is a kind of radioactive reactions where the reactant changes to new element by releasing an electron and thus there is a change in the atomic number of the product by one.

4 0
3 years ago
Convert the following: 52 miles/hour to meters/second
Komok [63]

Answer:

23.246 metres per second

Explanation:

divide the speed value by 2.237

5 0
3 years ago
Several forces act on an object at rest. It is known that the sum of the forces acting on the object is zero. Which statement is
MAVERICK [17]

Answer:

When net force of zero acting on a ball which is at rest , then the object center of mass will not accelerate , but the object may begin to rotate .

Explanation:

Here when there is an object where several forces are acing upon  are zero then the center of mass will not accelerate because we know that

    A_{com}=\frac{F_{net}}{M}

Where A_{com} = acceleration of center of mass  

            F_{net} = net force = 0

   So the acceleration of center of mass will be zero

But the torque ,may not be zero as torque is product of individual force and perpendicular force .

 Since if torque is not equal to zero then the object may begin to rotate

4 0
3 years ago
In Trial II, the same spring is used as in Trial I. Let us use this information to find the suspended mass in Trial II. Use 0.51
Masteriza [31]

Answer:

M_2=0.79kg

Explanation:

From the question we are told that:

Period T=0.517s

Trial 1

Spring constant \mu=117N/m

Period T_1=0.37

Mass m=0.400kg

Trial 2

Period T_2=0.52

Generally the equation for Spring Constant  is mathematically given by

\mu=\frac{4 \pi^2 M}{T^2}

Since

\mu _1=\mu_2

Therefore

\frac{4 \pi^2 M_1}{T_1^2}=\frac{4 \pi^2 M_2}{T_2^2}

M_2=M_1*(\frac{T_2}{T_1})^2

M_2=0.400*(\frac{0.52}{0.37}})^2

M_2=0.79kg

5 0
3 years ago
An initially stationary 4.3 kg object accelerates horizontally and uniformly to a speed of 11 m/s in 3.4 s. (a) In that 3.4 s in
Nataliya [291]

Answer:

The work done on the object by the force accelerating it is 520.31 J

Explanation:

Given;

mass of an object = 4.3 kg

horizontal velocity of the object, v = 11 m/s

time of acceleration, t = 3.4 s

work done is given as the product of force and distance

Work done = Fd

horizontal distance traveled by the object within 3.4 s, is calculated as follows;

X = Vt + ¹/₂gt², gravity has little or no influence on horizontal displacement, thus g = 0

X = Vt

X = 11*3.4 = 37.4 m

Force on the object, F = ma = m(v/t) = 4.3(11/3.4) = 13.912 N

work done = Fd = 13.912 x 37.4 = 520.31 J

Therefore, the work done on the object by the force accelerating it is 520.31 J

8 0
3 years ago
Read 2 more answers
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