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lesya692 [45]
3 years ago
8

A passenger in the rear seat of a car moving at a steady speed is at rest relative to

Physics
1 answer:
Ber [7]3 years ago
6 0
The person is at rest with respect to the car. So the best answer is:

c. the front seat of the car.

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At a particular instant the magnitude of the momentum of a planet is 2.05 × 10^29 kg·m/s, and the force exerted on it by the sta
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727.5256266 AWNSERrRrrRr
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3 years ago
A car is traveling with a velocity of 5.5 m/s and has a mass of 1200 kg. What is the kinetic energy?!
vesna_86 [32]

Answer:

<h2>18150 J</h2>

Explanation:

The kinetic energy of the car can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the Mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 1200 \times  {5.5}^{2}  \\  = 600 \times 30.25

We have the final answer as

<h3>18150 J</h3>

Hope this helps you

3 0
3 years ago
Where would aliens be if they really do exist here on Earth?​
AysviL [449]

Answer:

I would guess they'd probably be in an area they feel is habitatible.

7 0
3 years ago
Read 2 more answers
On a popular amusement park ride, the riders stand along the inside wall of a large cylinder with a diameter of 8.27 m. The cyli
____ [38]

Answer:

Explanation:

D = 8.27 m   ⇒  R = D / 2 = 8.27 m / 2 = 4.135 m

ω = 0.66 rev/sec = (0.66 rev/sec)*(2π rad/1 rev) = 4.1469 rad/s

We can apply the equation

Ff = W  ⇒  μ*N = m*g   <em>(I)</em>

then we have

N = Fc = m*ac = m*(ω²*R)

Returning to the equation <em>I</em>

<em />

μ*N = m*g    ⇒    μ*m*ω²*R = m*g   ⇒ μ = g / (ω²*R)

Finally

μ = (9.81 m/s²) / ((4.1469 rad/s)²*4.135 m) = 0.1379

3 0
3 years ago
Which type of energy will definitely not be used in the lighting of a match?
In-s [12.5K]
I say that the answere would be B
4 0
3 years ago
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