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lesya692 [45]
3 years ago
8

A passenger in the rear seat of a car moving at a steady speed is at rest relative to

Physics
1 answer:
Ber [7]3 years ago
6 0
The person is at rest with respect to the car. So the best answer is:

c. the front seat of the car.

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Studies have shown that viewing violent actions in the media __________ the inhibition against performing those actions, especia
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Decreases

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The layers of the fossil the oldest is usual the bottom layer,and the top layer is the newest layer

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Which law describes how the Earth applies a gravitational force on the Moon, the Moon applies a gravitational force on Earth? *
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The properties of elements can be predicted by which of the following?
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1 Answer. The Periodic Table can predict the properties of new elements, because it organizes the elements according to their atomic numbers. Creating new elements is not a simple process. Scientists use a particle accelerator to smash light atoms into a thin metallic foil that contains heavier atoms.

Explanation:

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3 years ago
An electron that has a velocity with x component 2.6 × 106 m/s and y component 3.2 × 106 m/s moves through a uniform magnetic fi
elena55 [62]

Answer:

a) \vec F_{B} = 8.766\times 10^{-14}\,T\,k, b) \vec F_{B} = -8.766\times 10^{-14}\,T\,k

Explanation:

a) The magnetic force experimented by a particle has the following vectorial form:

\vec F_{B} = q\cdot \vec v \times \vec B

The charge of the electron is equal to -1.602\times 10^{-19}\,C. Then, cross product can be solved by using determinants:

\vec F_{B} = \begin{vmatrix}i&j&k\\-4.165\times 10^{-13}\, C\cdot \frac{m}{s} &-5.126\times 10^{-13}\,C\cdot \frac{m}{s} &0\,C\cdot \frac{m}{s} \\0.041\,T&-0.16\,T&0\,T\end{vmatrix}

The magnetic force is:

\vec F_{B} = 8.766\times 10^{-14}\,T\,k

b) The charge of the proton is equal to 1.602\times 10^{-19}\,C. Then, cross product has the following determinant:

\vec F_{B} = \begin{vmatrix}i&j&k\\4.165\times 10^{-13}\, C\cdot \frac{m}{s} &5.126\times 10^{-13}\,C\cdot \frac{m}{s} &0\,C\cdot \frac{m}{s} \\0.041\,T&-0.16\,T&0\,T\end{vmatrix}

The magnetic force is:

\vec F_{B} = -8.766\times 10^{-14}\,T\,k

8 0
3 years ago
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