Answer:
the work required for the loading of second dart is 64 times greater as work required for loading the first dart.
Explanation:
k = spring constant of the spring loaded toy dart gun
x₁ = compression of spring to load the first dart = d
x₂ = compression of spring to load the second dart = 8 d
E₁ = Work required to load the first dart
E₂ = Work required to load the second dart
Work required to load the first dart is given as
E₁ = (0.5) k x₁² = (0.5) k d²
Work required to load the second dart is given as
E₂ = (0.5) k x₂² = (0.5) k (8d)² = (64) (0.5) k d²
E₂ = 64 E₁
So the work required for the loading of second dart is 64 times greater as work required for loading the first dart
Answer:
Two charged objects have a repulsive force of 0.080 N. If the charge of both of the objects is doubled, then what is the new force? Explanation: Electrostatic force is directly related to the charge of each object. So if the charge of both objects is doubled, then the force will become four times greater.
Explanation:
hope this helps
Explanation:
Given that,
Angle by the normal to the slip α= 60°
Angle by the slip direction with the tensile axis β= 35°
Shear stress = 6.2 MPa
Applied stress = 12 MPa
We need to calculate the shear stress applied at the slip plane
Using formula of shear stress

Put the value into the formula


Since, the shear stress applied at the slip plane is less than the critical resolved shear stress
So, The crystal will not yield.
Now, We need to calculate the applied stress necessary for the crystal to yield
Using formula of stress

Put the value into the formula


Hence, This is the required solution.
The mass of the hoop is the only force which is computed by:F net = 2.8kg*9.81m/s^2 = 27.468 N
the slow masses that must be quicker are the pulley, ring, and the rolling sphere.
The mass correspondent of M the pulley is computed by torque τ = F*R = I*α = I*a/R F = M*a = I*a/R^2 --> M = I/R^2 = 21/2*m*R^2/R^2 = 1/2*m
The mass equal of the rolling sphere is computed by: the sphere revolves around the contact point with the table. So using the proposition of parallel axes, the moment of inertia of the sphere is I = 2/5*mR^2 for spin about the midpoint of mass + mR^2 for the distance of the axis of rotation from the center of mass of the sphere. I = 7/5*mR^2 M = 7/5*m
the acceleration is then a = F/m = 27.468/(2.8 + 1/2*2 + 7/5*4) = 27.468/9.4 = 2.922 m/s^2
Answer:
For left = 0 N/C
For right = 0 N/C
At middle =
N/C
Explanation:
Given data :-
б =
C/ m²
Considering the two thin metal plates to be non conducting sheets of charges.
Electric field is given by

1) To the left of the plate
= 0 N/C.
2) To the right of them.
= 0 N/C.
3) Between them.
=
=
=
N/C