Which of the following has the greatest magnitude?

You hold a 0.125 kg glider A and a 0.500 kg glider B at rest on an air track with a compressed spring of negligible mass between

o-na [289]

Answer:

Magnitude |VB| = 0.32 m/s

and

Direction is to the left

Explanation:

given data

glider A mass = 0.125 kg

glider B mass = 0.500 kg

glider A move = 0.960 m to the left

solution

we use here Conservation of momentum that is

M1 × U1 + M2 × U2 =M1 × V1 + M2 × V2 ........................1

put here value and we get

0.125 × 0 + 0.500 × 0 = 0.125 × 0.960 + 0.375 × VB

VB = −0.32 m/s

Magnitude |VB| = 0.32 m/s

and

Direction is to the left

8 0

3 years ago

Is it possible for the velocity of an object to be zero and its acceleration not zero?

Nesterboy [21]

Explanation:

Yes, it is possible to have zero speed while accelerating, but only for a moment. ... acceleration is the rate at which the speed and direction of an object changes over time, so whenever an object goes through zero speed while reversing directions, it has non-acceleration. zero but a speed of zero.

8 0

3 years ago

Whic two types of cells are required during the process of osteogenesis

Mkey [24]

Answer:

Bone homeostasis involves multiple but coordinated cellular and molecular events. Two main types of cells are responsible for bone metabolism: osteoblasts (which secrete new bone), and osteoclasts (which break bone down).

Explanation:

3 0

3 years ago

A tightly wound 1000-turn toroid has an inner radius 1.00 cm and an outer radius 2.00 cm, and carries a current of 1.50 A. The t

V125BC [204]

Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT

Explanation:

Given;

Number of turns, N = 1000

Inner radius, r₁ = 1cm

Outer radius, r₂ = 2cm

Current, I = 1.5A

Magnetic field strength, B = ?

The magnetic field inside a tightly wound toroid is given by B = μ₀ NI / 2πr

where,

a < r < b and a and b are the inner and outer radii of the toroid.

The magnetic field of toroid is

$B = \frac{u_oNI}{2\pi r}$

Substituting the values in the formula:

$B (1.10cm) = \frac{(4\pi X 10^-^7 ) ( 1000)(1.5)}{2\pi (1.10) } \\\\$

$B (1.10cm) = 27.3mT$

Therefore, the magnitude of magnetic field at a distance 1.10cm from the origin is 27.3mT

7 0

3 years ago

PLS ANSWER FAST WILL MARK BRAINLIEST

densk [106]

In position A

The mirror has to be observed in the ray reflected from the mirror.

Since the the angle of reflection is equal to the angle of incidence, the reflected ray must be in equal path as the incident ray.

That phenomenon is only in diagram A

7 0

3 years ago