A Level is set up midway between two wood hubs that are about 300 ft. apart. The rod reading on hub A is 9.09 ft. and the readin
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Answer:
The friction force is 250 N
Explanation:
The desk is moving at constant velocity. This means that its acceleration is zero: a = 0. Newton's second law states that the resultant of the forces acting on the desk is equal to the product between mass (m) and acceleration (a):
In this case, we know that the acceleration is zero: a = 0, so also the resultant of the forces must be zero:
(1)
We are only interested in the forces acting along the horizontal direction, since it is the direction of motion. There are two forces acting in this direction:
- the pull, forward, F = 250 N
- the friction force, backward,
Given (1), we have
So the force of friction must be equal to the pull:
The distance of the motorboat relative to the home, which travels in various directions, is 3.07 km.
<h3>What is relative velocity?</h3>Relative velocity is a velocity of an object which is in respect to another observer, or it is a ratio of change in the position of a point to time with respect to another observer.
Given: Travel in East direction ()= 5 km,
velocity in N35E(v) = 2 m / s, time taken(t) = 90 min = 5400 seconds,
Displacement in south () = 6.5 km
Firstly, find the displacement in N35E so
Displacement = Velocity × time,
= 2 × 5400 = 10800 meters or 10.8 km
Now by using Pythagoras' theorem
We can calculate the return displacement in the south direction(),
=
=
= 9.57 km
Therefore, the distance of the boat from the home (D) = -
D = 9.57 - 6.5;
D = 3.07 Km
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