How much work is done by the force lifting a
1 answer:
The work done in lifting the hamburger is equal to the increase in gravitational potential energy of the hamburger, given by
where
m=0.1 kg is the mass of the hamburger
is the gravitational acceleration
is the increase in height of the hamburger
Substituting numbers into the equation, we find
So, the correct answer is
(3) 0.3 J
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The sprinter is in uniform accelerated motion, and its initial velocity is zero, so the relationship betwen space (S) and time (t) is
where a is the acceleration. Using the data of the problem, we can find a:
So now we can solve the 3 parts of the problem.
a) power output at t=2.0 s
The velocity at t=2.0 s is
the kinetic energy of the sprinter is
and so the power output is
b) power output at t=4.0s
The velocity at t=4.0 s is
the kinetic energy of the sprinter is
and so the power output is
c) Power output at t=6.0 s
The velocity at t=2.0 s is
the kinetic energy of the sprinter is
and so the power output is
where a is the acceleration. Using the data of the problem, we can find a:
So now we can solve the 3 parts of the problem.
a) power output at t=2.0 s
The velocity at t=2.0 s is
the kinetic energy of the sprinter is
and so the power output is
b) power output at t=4.0s
The velocity at t=4.0 s is
the kinetic energy of the sprinter is
and so the power output is
c) Power output at t=6.0 s
The velocity at t=2.0 s is
the kinetic energy of the sprinter is
and so the power output is
Answer:
66.35m/s
Explanation:
Para resolver el ejercicio es necesario la aplicación de las ecuaciones de continuidad, que expresan que
From our given data we can lower than:
So using the continuity equation we have
Therefore the velocity at the exit end is 66.35m/s