If the lightbulb A in the circuit shown in the image burned out, the path for the current to flow is disrupted because one of its terminals is connected direct to the source. So, there will be no current through the lightbulbs B, C, and D, and they will turn off. Similarly it will happen, if the lightbulb D burned out.
If the lightbulb B burned out the current will continue circulating through the lightbulbs A, C, and D, because lightbulb B is connected in parallel. Similarly it will happen, if the lightbulb C burned out.
Answer:
3 m/sec(squared)
Explanation:
a=change in velocity/time
a=v-u/t
a=36-0=36/12
a=3m/s(squared)
Coal plants use a boiler to produce steam.
Explanation:
Initial speed of blood, u = 0
Final speed of the blood, v = 26 cm/s
(a) Displacement of the blood, d = 2 cm
Let a be its acceleration. It can be calculated using third equation of motion as :
(b) Let t is the time taken by the blood to reach its final speed. It can be calculated as :
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t = 0.15 s
Hence, this is the required solution.
