4) x=4 -> divide by 2
5) y=9 -> add 2
6) z=2 -> multiply 2 times 1
7) a=10 -> add 7 then divide by 3
8) b=3 -> distributive property, add 1 to other side, and then divide by 8
9) c= -d +4 -> subtract +d+1 and put on other side to solve
10) m= 10/p+2 -> distrubutive property, subtract 2m on both sides to solve
For every one part, or in this case 200 ml of shampoo, there are three parts water. This means that there is 6 times more water than shampoo. 200 * 6 = 1200 ml of water
"<span>The diagonals bisect each other" is the one property among the following choices given in the question that you would </span><span>use to prove AEB ≅ DEC by SAS. The correct option among all the options that are given in the question is the second option. I hope that this is the answer that has actually come to your desired help.</span>
let's not scratch sin(x), she may not like it anyway, but let's do some stretching by checking this template
![\bf ~~~~~~~~~~~~\textit{function transformations} \\\\\\ f(x)=Asin(Bx+C)+D \\\\ f(x)=Acos(Bx+C)+D\\\\ f(x)=Atan(Bx+C)+D \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \bullet \textit{ stretches or shrinks}\\ ~~~~~~\textit{horizontally by amplitude } A\cdot B\\\\ \bullet \textit{ flips it upside-down if }A\textit{ is negative}\\ ~~~~~~\textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if }B\textit{ is negative}\\ ~~~~~~\textit{reflection over the y-axis}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bfunction%20transformations%7D%20%5C%5C%5C%5C%5C%5C%20f%28x%29%3DAsin%28Bx%2BC%29%2BD%20%5C%5C%5C%5C%20f%28x%29%3DAcos%28Bx%2BC%29%2BD%5C%5C%5C%5C%20f%28x%29%3DAtan%28Bx%2BC%29%2BD%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cbullet%20%5Ctextit%7B%20stretches%20or%20shrinks%7D%5C%5C%20~~~~~~%5Ctextit%7Bhorizontally%20by%20amplitude%20%7D%20A%5Ccdot%20B%5C%5C%5C%5C%20%5Cbullet%20%5Ctextit%7B%20flips%20it%20upside-down%20if%20%7DA%5Ctextit%7B%20is%20negative%7D%5C%5C%20~~~~~~%5Ctextit%7Breflection%20over%20the%20x-axis%7D%20%5C%5C%5C%5C%20%5Cbullet%20%5Ctextit%7B%20flips%20it%20sideways%20if%20%7DB%5Ctextit%7B%20is%20negative%7D%5C%5C%20~~~~~~%5Ctextit%7Breflection%20over%20the%20y-axis%7D)
A = 1/5, so then .......... 
The answer is D, or 168.
The cheese can be any one out of 3 = 3 choices. For each of those . . .
The first topping can be any one of 8. For each of those . . .
The second topping can be any one of the remaining 7 . For each of those . . .
The third topping can be any one of the remaining 6 .
Total number of ways to assemble a pizza = (3 x 8 x 7 x 6) = 1,008 ways.
<span>BUT . . . </span>
You could choose the SAME 3 toppings in (3 x 2) = 6 different ways, and
nobody could tell the difference once they were selected. All 6 different
ways would result in the same pizza.
So, out of the 1,008 total different ways there are of choosing ingredients,
<span>there are only ( 1,008 / 6 ) = </span>168<span> different and distinct pizzas.</span>
