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Viktor [21]
4 years ago
7

What is the solution to x ? 7/3x + 1/3x = 3x + 6/3 + 5/3x

Mathematics
1 answer:
nignag [31]4 years ago
7 0
7/3x+1/3x=3x+6/3+5/3x
8/3x-5/3x=3x+6/3
3/3x=3x+6/3
x=3x+6/3
x-3x=6/3
-2x=2
-x=2/2
-x=1
x=-1
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What is the fifth term in the expansion of (3x - 3y)7? <br> __ x3y4
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(r+1)th term of (a +x)^n = nCr a^(n-r)x^r

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Step-by-step explanation:

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3 years ago
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Consider the line that passes through each pair of given points, and decide what type of slope the line has.
tatiyna

Answer:

The types of slope for each pair are:

(2, 4) and (5, 1) => Negative

(3,5) and (-1,2) => Positive

(-7, 8) and (-7,0) => Undefined

(6.-3) and (4, -3) => Zero

Step-by-step explanation:

We will find the slope of each line to check the type of slope.

Slope is given by the formula:

m = \frac{y_2-y_1}{x_2-x_1}

Here (x1,y1) are the coordinates of first point and (x2,y2) are coordinates of second point

Now,

<u>(2, 4) and (5, 1)</u>

m = \frac{1-4}{5-2} = \frac{-3}{3} =-1

The slope is negative.

<u>(3,5) and (-1,2)</u>

m = \frac{2-5}{-1-3} = \frac{-3}{-4} = \frac{3}{4}

The slope is positive

(-7, 8) and (-7,0)

m = \frac{0-8}{-7+7} = \frac{-8}{0}

division by zero makes the slope undefined.

(6.-3) and (4, -3)

m=\frac{-3+3}{4-6} = \frac{0}{-2} = 0

The slope is zero

Hence,

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(2, 4) and (5, 1) => Negative

(3,5) and (-1,2) => Positive

(-7, 8) and (-7,0) => Undefined

(6.-3) and (4, -3) => Zero

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answer (0,10) see pic:


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