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UNO [17]
3 years ago
15

Suppose that a CPU scheduling algorithm favors those processes that have used the least processor time in the recent past. Why w

ill this algorithm favor I/O-bound programs and yet not permanently starve CPU-bound programs?
Computers and Technology
1 answer:
avanturin [10]3 years ago
6 0

Answer:

I/O bound programs will be favored due to the CPU burst request of the I/O programs. This is because their CPU burst request is short and would release the CPU within a short period.

Due to the brief request time of the I/O programs on the CPU, CPU-bound programs will not be permanently starved. After a little while, CPU resources will be released to the CPU-bound programs for use.

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The answer to your question is true
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Namecoin is an alternative blockchain technology that is used to implement decentralized version of Routing Banking System.A. Tr
vova2212 [387]

Answer:

False

Explanation:

Namecoin is a type of crypto currency which was originally pronged from Bitcoin software. It is coded in the fashion of Bitcoin with the same algorithm as well. Hence it is not a blockchain technology that is used to implement decentralized version of Routing Banking System. Namecoin can store data within its own blockchain transaction database.

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A Uniform Resource Locator (URL) consists of three separate parts: network protocol, host, and web browser.
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Write a program FindDuplicate.java that reads n integer arguments from the command line into an integer array of length n, where
kozerog [31]

Answer:

  1. public class FindDuplicate{
  2.    public static void main(String[] args) {
  3.        Scanner input = new Scanner(System.in);
  4.        int n = 5;
  5.        int arr[] = new int[n];
  6.        for(int i=0; i < arr.length; i++){
  7.            int inputNum = input.nextInt();
  8.            if(inputNum >=1 && inputNum <=n) {
  9.                arr[i] = inputNum;
  10.            }
  11.        }
  12.        for(int j =0; j < arr.length; j++){
  13.            for(int k = 0; k < arr.length; k++){
  14.                if(j == k){
  15.                    continue;
  16.                }else{
  17.                    if(arr[j] == arr[k]){
  18.                        System.out.println("True");
  19.                        return;
  20.                    }
  21.                }
  22.            }
  23.        }
  24.        System.out.println("False");
  25.    }
  26. }

Explanation:

Firstly, create a Scanner object to get user input (Line 4).

Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).

Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.

If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".

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almond37 [142]
Yes, your search results are based on your location, if you allow safari to use your location (phone)
8 0
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