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4 years ago

Help Plz ASAP!!!!!!

Mathematics

1 answer:

Zigmanuir [339]4 years ago

8 0

Answer: ( t - 5)* 210 = 41790

T=204

Step-by-step explanation:

Believe me my friend

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To the nearest hundredth, what is the value of m?

Aleksandr-060686 [28]

Answer:

MEH

Step-by-step explanation:

THE DEMON WILL BE UN AMERICAN IN ORDER FOR A ICE BALL AND THE OTHER IS A SIMP OF A BAT OR SOMETHING THAT IS NOT A GOOD SHOE OR SOMETHING LIKE THIS ONE THAT HAS BEEN TRYING FOR THE PAST THREE YEARS OF THE HW ERA AND THE ONLY ONE I HAVE SOMETHING THAT IS NOT THAT MUCH YOUR JUST BROKE

7 0

4 years ago

A garden hose sprays 24 gallons of water in 1 minute. The ratio of pints to gallons is 8 to 1.

Harlamova29_29 [7]

Answer:

192

Step-by-step explanation:

24 * 8 (number of pints in a gallon)

8 0

2 years ago

Read 2 more answers

A city planner needs to make a model of the city. In real life, the city courthouse is 60 feet tall. A building across the stree

horsena [70]

I got 1.33 (On a calculator)

8 0

4 years ago

Plz help i am so busy plz plz help me

stiv31 [10]

D=60
DEC=50
CER=130

(X=30)

4 0

3 years ago

Read 2 more answers

Which statement describes the inverse of m(x) = x^2 – 17x?

DochEvi [55]

Given:

The function is

$m(x)=x^2-17x$

To find:

The inverse of the given function.

Solution:

We have,

$m(x)=x^2-17x$

Substitute m(x)=y.

$y=x^2-17x$

Interchange x and y.

$x=y^2-17y$

Add square of half of coefficient of y , i.e., $\left(\dfrac{-17}{2}\right)^2$ on both sides,

$x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

Taking square root on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}$

Add $\dfrac{17}{2}$ on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y$

Substitute $y=m^{-1}(x)$ .

$m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$

We know that, negative term inside the root is not real number. So,

$x+\left(\dfrac{17}{2}\right)^2\geq 0$

$x\geq -\left(\dfrac{17}{2}\right)^2$

Therefore, the restricted domain is $x\geq -\left(\dfrac{17}{2}\right)^2$ and the inverse function is $m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$ .

Hence, option D is correct.

Note: In all the options square of $\dfrac{17}{2}$ is missing in restricted domain.

7 0

3 years ago

Help Plz ASAP!!!!!!​

Help Plz ASAP!!!!!!