Answer:
The minimum speed when she leave the ground is 6.10 m/s.
Explanation:
Given that,
Horizontal velocity = 1.4 m/s
Height = 1.8 m
We need to calculate the minimum speed must she leave the ground
Using conservation of energy
Put the value into the formula
Hence, The minimum speed when she leave the ground is 6.10 m/s.
Here in order to find out the distance between two planes after 3 hours can be calculated by the concept of relative velocity
here
speed of first plane is 700 mi/h at 31.3 degree
speed of second plane is 570 mi/h at 134 degree
now the relative velocity is given as
now the distance between them is given as
so the magnitude of the distance is given as
miles
so the distance between them is 2985.6 miles
Answer:
The energy loss due to friction is 9465 J.
Explanation:
The given data :-
Mass of roller (m) = 500 kg.
The speed of roller coaster at height 27 m = 5.6 m/s.
Initial height of roller( h ) = 27 m.
The speed of roller coaster at bottom = 22 m/s.
Initial energy of roller at a height 27 m.
E₁ = K.E + P.E
E₁ = = = 7840 + 132435
E₁ = 140,275 J
The energy of roller at a height 2 m.
E₂ = K.E + P.E
E₂ = = = 121000 + 9810
E₂ = 130,810 J
The energy loss due to friction = E₁ - E₂ = 140,275 - 130,810 = 9465 J.
Light to Electric to kinetic
Answer:
And for this case we can write this expression like this:
The velocity would be given by the first derivate and we got:
And the maximum velocity would be:
Explanation:
For this case we have the following function for the position:
And for this case we can write this expression like this:
The velocity would be given by the first derivate and we got:
And the maximum velocity would be: