Answer:
A stop watch measures time and the number of seconds making an osculation is the period T
Which is T = 2π√(L/g)........solving for L (the length of the pendulum),
Then the L = T²x g/( 4πr²) substitute and then u find length or height of the swing
Answer:
f' = 3665.51 Hz
Explanation:
given,
speed of the hawk = 24.7 m/s
frequency of screech emitted by the hawk = 3400 Hz
speed of sound = 331 m/s
By Doppler's effect
f' is the frequency received by the mouse
v is the speed of the sound
v_s is the speed of the hawk
now,
f' = 1.078 x 3400
f' = 3665.51 Hz
The frequency received by the stationary mouse is equal to 3665.51 Hz
If the resulting compound feels hot, then it is exothermic. Otherwise, it is endothermic.
Catalysts and inhibitors both affect the reaction rate of a chemical reaction. A catalyst speeds up the rate of reaction, while an inhibitor does the opposite (slows down the reaction rate).
Answer:
With more air is more buoyancy. When deflated or released the scuba diver is less buoyant.
Explanation:
The compensator is a Buoyancy control device that has an inflatable air bladder.When we have more air out into the inflatable bladder, then one is more buoyant. If the air is released from the bladder, then one is less buoyant. We add air through an air inflation valve. Air is also then released using air-deflation valves.
Buoyancy can be defined as an upward force which is exerted on an object that is fully or partially immersed in water
when one is less buoyant than water, it means that the upward pressure is more than the downward pressure of that person and his equipment. Then he will float. In a case of negative buoyancy, we have downward pressure of this person and his equipment to be more than the upward pressure of the water. Then sinking will happen.
The net force (magnitude and direction) of the system given in the question is 40 N horizontal to the right
<h3>How to determine the net force</h3>
Case 1 (Net force between up and downward force)
- Force up (Fu) = 50 N
- Force down (Fd) = 30 N
- Net force 1 (F1) = ?
F1 = Fu - Fd
F1 = 50 - 30
F1 = 20 N up
Case 2 (Net force between right and left)
- Force right (Fr) = 60 N
- Force left (Fl) = 20 N
- Net force 2 (F2) = ?
F2 = Fr - Fl
F2 = 60 - 20
F2 = 40 N right
SUMMARY
- Net force between up and down = 20 N up
- Net force between right and left = 40 N right
From the above, the net force between right and left (i.e 40 N) is greater than the net force between up and down (i.e 20 N)
Thus, the net force of the system will be 40 N horizontal to the right
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