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Vanyuwa [196]
3 years ago
12

Which barium nitrate solution requires the greatest moles of solute?

Chemistry
1 answer:
DochEvi [55]3 years ago
6 0

Answer:

The answer to your question is: letter E,  1.77 L of 1.55 M Ba(NO3)2

Explanation:

Formula

Molarity = \frac{moles}{volume (L)}

moles = Molarity x volume (L)

a. 2.58 L of 0.0250 M Ba(NO3)2

moles = (0.025) (2.58)

moles = 0.065 M

b. 19.23 mL of 8.5 × 10−2 M Ba(NO3)2

moles = (8.5 x 10 ⁻²) (0.01923)

moles = 0.0016

c. No right answer.

d. 26.20 mL of 2.21 M Ba(NO3)2

 moles = (2.21)(0.0262)

moles = 0.058

e. 1.77 L of 1.55 M Ba(NO3)2

  moles = (1.55)(1.77)

  moles = 2.74            This solution needs the greatest concentration of

                                    Ba(NO₃)₂

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A glass flask whose volume is 1000 cm3 at a temperature of 0.800 C is completely filled with mercury at the same temperature. Wh
ira [324]

Answer: the coefficient of volume expansion of glass = 0.86/(1000 * 52) = 0.00001654 per degree.

Explanation:

Original volume of mercury = 1000 cm3.

The final volume of mercury considering its volume expansion quotient = 1000 + 1000*(1.8*10^-4 *52) = 1000 + 9.36 = 1009.36 cm^3

Considering the glass as a non expanding substance, the complete excess volume of 9.36 cm3 of mercury should have overflown the container, but due to the expansion of glass, the capacity of mercury containment increases and so a lesser amount of mercury flows out.

The amount of mercury that actually flowed out = 8.50 cm3.

So, the expansion of the glass container = 9.36-8.50 = 0.86 cm3.

Using the formula for coefficient of expansion,

coefficient of volume expansion of glass = 0.86/(1000 * 52) = 0.00001654 per degree.

5 0
3 years ago
what would the molarity of a solution be if you took 10 mL of a 13M stock solution and made a 300 mL solution?
nignag [31]

Answer:

0.43M

Explanation:

8 0
3 years ago
An alpha particle is equivalent to the nucleus of an atom of which element?(1 point)
Katyanochek1 [597]

Answer:

this is what i got

Explanation:

α-decay: When a radioactive nucleus disintegrates by emitting an αα-particle, the atomic number decreases by two and mass number decreases by four. Example: 88​Ra226→86​Rn222+2​He4.

3 0
2 years ago
A certain reaction with an activation energy of 205 kj/mol was run at 485 k and again at 505 k . what is the ratio of f at the h
lapo4ka [179]
Arrhenius' Law relates activation energy, Ea, rate constant, K, and temperature, T as per this equation:

K (T) = A * e ^ (-Ea / RT), where R is the universal constant of gases and A is a constant which accounts for collision frequency..

Then you can find the ration between K's at two different temperatures as:

K1 = A * e ^ (-Ea / RT1)

K2 = A* e ^(-Ea / RT2)

=> K1 / K2 = e ^ { (-Ea / RT1) - Ea / RT2) }

=> K1 / K2 = e ^ {(-Ea/ R ) *( 1 / T1 - 1 T2) }

=> K1 / K2 = e^ { (-205,000 j/mol / 8.314 j/mol*k )* ( 1 / 505K - 1/ 485K) }

=> K1 / K2 = e ^ (2.0134494) ≈ 7.5

Answer: 7.5




8 0
3 years ago
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