Answer: T<span>
etrafluoroethene (F</span>
₂CCF₂<span>
) undergoes polymerization describes the formation of Teflon.
Explanation: Polymerization is the process in which small units called as
monomers join together repeatedly and forms a long chain macro-molecule called as
polymer.
In given question the monomer is Tetrafluoroethene because alkenes can undergo polymerization via Addition polymerization via following mechanism.
a) Free Radical Addition Reaction
b) Acid Catalyzed Addition Reaction
c) Base catalyzed Addition Reaction
The formation of
Teflon from Tetrafluoroethene is shown below,</span>
Answer: An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions. Ionic bonds are formed between a cation, which is usually a metal, and an anion, which is usually a nonmetal.
basically explains
Answer:
cu+2 ------ oxidation whereas Cu ------ reduction.
Explanation:
In the reaction, cu+2 is the place where oxidation occurs because this cupric ion losses electrons which causes +2 charge on it. we know that oxidation is the loss of electrons and reduction is the gaining of electrons so the Cu is the place or atom at which reduction occurs. Electrochemical cells have two electrodes, which is anode and the cathode. The anode is the electrode where oxidation occurs whereas the cathode is the electrode where reduction takes place.
Answer:
Model B
Explanation:
Model A shows that light has been reflected, whereas Model B shows the light has been refracted. Light will be refracted as the light enters a more dense medium (glass), from a less dense medium (air).
This website has a really useful, thorough explanation for why this occurs:
(Check the explanation under the heading 'Explaining refraction - Higher')
https://www.bbc.co.uk/bitesize/guides/zw42ng8/revision/2
Hope this helps!
Explanation:
Set up the ion formation equations, with ionization energy values for each electron in the valence layer, of the atoms of the chemical elements below: a) Na z=11 b) Ca z= 20 c) Sr z 38 d) Li z= 3 e) Cs z= 55 f) Be z= 43