A kilogram %30 chocolate,
b kilogram %50 chocolate,
a+b = 100 kilogram chocolate,
48.(a+b) = 30.a + 50.b
48a + 48b = 30a + 50b
18a = 2b
b = 9a
a+b = a + 9a = 10a = 100 kg
a = 10 kg
b = 9.a = 90 kg
You should use,
10 kg %30 chocolate,
90 kg %50 chocolate
Answer and Step-by-step explanation:
a.)x^2 and y^2 are always greater than zero.(assuming real x and y).
=>x^2<=x^2+y^2
=>|x|(x^2)<=|x|(x^2+y^2)
=>|x^3|<=|x|(x^2+y^2)
b. similarly, |y^3|<=|y|(x^2+y^2)
=>|f(x,y)|=|x^3+y^3|/(x^2+y^2)=|x|+|y|
c. let h is very small number (close to zero but positive)
lim (x,y)-> (0,0) f(x,y)=(x^3+y^3)/(x^2+y^2)
putting x=h and y=h and approaching h->0
lim h->0 f(h)=2h=0
There is another explanation attached below
Sorry for the bad handwriting.
The answer is 64 fluid ounces
Answer:
36π
Step-by-step explanation:
d= 6 in
r= d/2=6/2= 3 in
volume of sphere= 4/3πr^3
=4/3 ×π×3^3
=36π in^3