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3 years ago

How many protons and electrons are in Hg+

Chemistry

1 answer:

Gala2k [10]3 years ago

8 0

Answer:

There are 80 protons and 80 electrons in Hg+ (Mercury)

Explanation:

Name Mercury

Symbol Hg

Atomic Number 80

Atomic Mass 200.59 atomic mass units

Number of Protons 80

Number of Neutrons 121

Number of Electrons 80

Melting Point -38.87° C

Boiling Point 356.58° C

Density 13.456 grams per cubic centimeter

Normal Phase Liquid

Family Transitions Metals

Period Number 6

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An isotope with a half life of 10 min and a starting sample size of 100 g would have

IgorC [24]

Answer:

12.5 gm left

Explanation:

30 minutes is THREE half lives

1/2^3 = 1/8th would be left

100g * 1/8 = 12.5 gm

7 0

2 years ago

What determines the precision of calculated results based on measurements

egoroff_w [7]

How small the unit of measurement is. The smaller the unit of measurement the more precise it is.

6 0

4 years ago

How many grams of silver chloride can be produced by reacting excess silver nitrate with 2.4 moles of zinc chloride? _____AgNO3

worty [1.4K]

<h3>Answer:</h3>

690 g AgCl

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Writing Compounds

<u>Stoichiometry</u>

Using Dimensional Analysis
Limiting Reactant/Excess Reactant

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] AgNO₃ + ZnCl₂ → AgCl + Zn(NO₃)₂

↓

[RxN - Balanced] 2AgNO₃ + ZnCl₂ → 2AgCl + Zn(NO₃)₂

[Given] 2.4 mol ZnCl₂

[Solve] <em>x</em> g AgCl

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol ZnCl₂ → 2 mol AgCl

[PT] Molar Mass of Ag - 107.87 g/mol

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of AgCl - 107.87 + 35.45 = 143.32 g/mol

<u>Step 3: Stoich</u>

[DA] Set up: $\displaystyle 2.4 \ mol \ ZnCl_2(\frac{2 \ mol \ AgCl}{1 \ mol \ ZnCl_2})(\frac{143.32 \ g \ AgCl}{1 \ mol \ AgCl})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 687.936 \ g \ AgCl$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

687.936 g AgCl ≈ 690 g AgCl

5 0

3 years ago

What is the mass of 5.35×1021 platinum atoms?

inysia [295]

Atomic weight of a Platinum:
195.078 u = 195.078 * 1.66 * 10^(-27) kg = 3.2382948 * 10^(-25) kg
m ( Pt ) = 3.2382948 * 10^(-25) * 5.35 * 10^(21) =
= 1.732488 * 10^(-3) kg = 1.732448 g

6 0

4 years ago

What mass of oxygen reacts with 4.62 g of magnesium to form magnesium oxide according to the following... 2 Mg O2 --> MgO

Goryan [66]

Answer:

3.08 g of Oxygen .

Explanation:

2Mg + O₂ = 2MgO

2 mole 1 mole

molecular weight of Mg = 24

2 mol of Mg = 48 g

48 g of Mg reacts with 32 g of oxygen

4.62 g of Mg will reacts with 3.08 g of Oxygen .

7 0

4 years ago