And the answer is False,it does not have the same number with particles as the one mole of hydrogen.
(P1)(V1)/(T1)=(P2)(V2)/(T2)
Set up as: (P1)(V1)(T2)/(T1)(P2)=(V2)
P1=207torr
V1=30.0L
T1=-268°C
P2=101.3kPa (Same as 760torr)(use torr to make it easier though)
T2=20.0°C
Make sure all °C is in Kelvin
°C + 273 = Kelvin
Numbers are now:
P1=207torr
V1=30.0L
T1=5K
P2=760torr
T2=293K
Set them up as shown above
Should look like this:
(207torr)(30.0L)(293K)/(5K)(760torr)=V2
As long as you do them in that order you should get: 478.82L
You can also round to get 479L
Either one is correct.
Answer:
Explanation:
The pressure is constant, so we can use Charles' Law.
Data:
V₁ = 1.92 × 10³ L; T₁ = 20 °C
V₂ = ?; T₂ = 68 °C
Calculations:
(a) Convert temperatures to kelvins
T₁ = (20 + 273.15) K = 293.15 K
T₂ = (68 + 273.15) K = 341.15 K
(b) Calculate the volume
The new volume of the gas is .
Answer:
Lithium hydroxide is a base.
Carbon dioxide is the anhydride of the carbonic acid, H₂CO₃.
Therefore, the reaction awaited is a typical neutralization reaction with the formation of a salt and water.
2LiOH + CO₂ → Li₂CO₃ + H₂O
So, 2*20 = 40 moles of LiOH react with 20 moles of CO₂.
Molar Mass of LiOH = 23.95 g/mol
So, 40 * 23.95 = 958 g